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Base Impedance (Per-Unit System)

Defines the reference impedance used to convert power system quantities into the per-unit system.

Power SystemsPer-Unit System

Base Impedance Calculator Per‑Unit System

Zbase = Vbase² / Sbase
Zbase = base impedance  ·  Vbase = base voltage  ·  Sbase = base power (usually 3‑phase MVA)
⟹ Solve Zbase, Vbase, Sbase
Ω
V (line‑to‑line)
MVA (3‑phase)
Please fix the errors above.
Solve for:
Presets:
Base Impedance
Zbase: Vbase: Sbase:
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Base Impedance Gauge
Low (< 1 Ω) Moderate (1–10 Ω) High (> 10 Ω)
Zbase = Vbase² / Sbase  ·  For 3‑phase systems, use line‑to‑line voltage (kV) and 3‑phase MVA.

Interpretation

Base impedance in the per‑unit system is Z_base = V_base² / S_base.
It provides a reference impedance for normalising system parameters.
Example: V_base=11kV, S_base=100MVA → Z_base = (11,000)² / 100,000,000 = 1.21Ω.

Z_base = V_base² / S_base
Base Impedance (Per-Unit System)

Variables

SymbolQuantityUnit
Z_baseBase impedanceΩ
V_baseBase voltage (line-to-line RMS)kV
S_baseBase apparent power (three-phase)MVA

What it means

In the per‑unit system, quantities are expressed as fractions of base values. Base impedance is defined as Z_base = V_base² / S_base, where V_base is the base voltage and S_base is the base power. This allows normalisation of impedances and simplifies calculations in power systems with multiple voltage levels. The per‑unit system eliminates the need for transformer ratios and makes it easier to compare equipment ratings. It is widely used in power system analysis, fault calculations, and protective relay coordination. The base values are chosen arbitrarily but should reflect the system’s nominal voltage and power. Example: For a system with V_base = 11 kV and S_base = 100 MVA, Z_base = (11,000)² / 100,000,000 = 121,000,000 / 100,000,000 = 1.21 Ω. An actual impedance of 2.42Ω would be 2.42/1.21 = 2.0 per unit.

Worked example

Base Impedance – Practical Example

Real‑World
Scenario: In a 11 kV system with a base power of 100 MVA, calculate the base impedance.
ParameterValue
Vbase11 kV
Sbase100 MVA
FormulaZbase = Vbase² / Sbase
1Convert units: V = 11,000 V, S = 100,000,000 VA
2Compute V² = 121,000,000
3Divide: 121,000,000 / 100,000,000 = 1.21 Ω
Final Design Zbase = 1.21 Ω ✓ Reference impedance
Why: Base impedance is used in per‑unit calculations to normalize system impedances for easy analysis.

Common mistakes

  • V_base: The base voltage (line‑to‑line for three‑phase systems).
  • S_base: The base apparent power (usually MVA or kVA).
  • Units: Ensure V_base and S_base use consistent units (e.g., kV and MVA).
  • Per‑unit system: Normalises quantities for easier analysis.
  • Transformer: Base impedance changes when crossing transformer boundaries.

Applications

Base impedance in the per‑unit system is Z_base = V_base²/S_base, providing a reference for normalising parameters. The per‑unit system simplifies the analysis of power systems by eliminating transformer ratios and allowing comparison of equipment of different ratings. Engineers use it for load flow, fault analysis, and stability studies. By using per‑unit values, they can avoid mistakes and focus on the relative values. Understanding base impedance is essential for working with the per‑unit system, which is standard in power system analysis. This formula is a key part of system modelling.

  • Power system modelling using per‑unit system
  • Load flow analysis and fault studies
  • Transformer and generator data representation
  • Standardised comparison of equipment ratings
  • Educational foundation of per‑unit calculations

Frequently Asked Questions

Q01What is base impedance in the per-unit system?
A01

Base impedance is defined as Z_base = V_base² / S_base, where V_base is the base voltage and S_base is the base power. It is used to convert actual impedances to per-unit values.

Q02What is the advantage of using per-unit quantities?
A02

It simplifies calculations, makes transformers transparent, and allows comparison of equipment of different ratings.

Q03How do you convert ohms to per-unit?
A03

Z_pu = Z_ohm / Z_base, where Z_base = V_base² / S_base (single-phase) or V_base² / S_base (three-phase, with line-to-line voltage).

Q04What is the base voltage and base power in a system?
A04

They are chosen arbitrarily; for a power system, common base values are 100 MVA and the nominal voltage of the system.

Q05How does the per-unit system handle transformers?
A05

The per-unit impedance remains the same on both sides of an ideal transformer, eliminating the turns ratio from calculations.

Q06What are typical per-unit reactance values for generators?
A06

Subtransient: 0.1-0.2 pu; transient: 0.2-0.3 pu; synchronous: 1.5-2.5 pu (for large generators).

Q07How do you change the base of a per-unit quantity?
A07

Z_pu_new = Z_pu_old × (V_base_old/V_base_new)² × (S_base_new/S_base_old).

Q08What is the per-unit system for three-phase circuits?
A08

Use line-to-line voltage and three-phase power as bases; the formulas are consistent if all quantities are per-phase or per-phase.

Q09What are the limitations of the per-unit system?
A09

It requires careful selection of bases and is only valid for linear systems; non-linearities must be handled separately.

Q10What are the common mistakes when using per-unit values?
A10

Common errors include: 1) using the wrong base values, 2) mixing up line and phase quantities, 3) forgetting to convert impedances, 4) applying to non-linear systems, and 5) using the wrong transformer tapping.