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Change in Entropy (Reversible Process)

Calculates the change in entropy of a system undergoing a reversible heat transfer at constant absolute temperature.

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Entropy Change CalculatorReversible Process

ΔS = Q / T
ΔS = entropy change (J/K)  ·  Q = heat transfer (J)  ·  T = absolute temperature (K)
⟹ SolveΔS, Q, T
J/K
J
K
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Presets:
Entropy Change
ΔS: Q: T:
Valid for reversible, isothermal processes. T must be in Kelvin.
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Entropy Change Magnitude
Small (< 1 J/K) Medium (1–5 J/K) Large (5–10 J/K) Very Large (> 10 J/K)
ΔS = Q / T  ·  For reversible isothermal processes. Units: J/K.

Interpretation

Change in entropy for reversible process: ΔS = Q/T, where Q is heat transferred reversibly at temperature T. Entropy is a measure of disorder. Example: 100 J heat added at 300 K → ΔS = 0.333 J/K.

delta_S = Q / T
Change in Entropy (Reversible Process)

Variables

SymbolQuantityUnit
delta_SChange in entropyJ/K
QHeat transferred (reversibly)J
TAbsolute temperature at which the transfer occursK

What it means

Entropy change is defined for a reversible process as the ratio of the heat exchanged to the absolute temperature. This is a state function, meaning ΔS depends only on initial and final states. The second law of thermodynamics states that for any spontaneous process, the total entropy of the universe increases. Entropy is often described as a measure of disorder or randomness. The formula is used in thermodynamics to analyse heat engines, refrigerators, and chemical reactions. It is also crucial in statistical mechanics (Boltzmann formula S = k ln W). Understanding entropy and its changes is fundamental for energy conversion efficiency and for predicting the direction of processes.

Worked example

Change in Entropy – Two Examples

Real‑World
Scenario: 1000 J of heat is added reversibly to a system at 300 K. Find the entropy change.
ParameterValue
Q1000 J
T300 K
1ΔS = Q/T = 1000/300 = 3.33 J/K
Result 3.33 J/K ✓ Positive
Scenario: 500 J of heat is removed from a system at 250 K. Find ΔS.
ParameterValue
Q-500 J
T250 K
1ΔS = -500/250 = -2.0 J/K
Result -2.0 J/K ✓ Negative
Key insight: ΔS = Q_rev/T – entropy increases for heat added, decreases for heat removed.

Common mistakes

  • Reversible process: This formula applies to reversible processes only – for irreversible, ΔS > Q/T.
  • Temperature T: In kelvin (absolute) – not Celsius.
  • Heat Q: The heat transferred reversibly – in joules.
  • Sign: Heat added to the system (positive Q) increases entropy; heat removed decreases entropy.
  • Entropy is a state function: ΔS depends only on initial and final states, not the path – but the calculation of Q/T is path‑dependent for irreversible paths.

Applications

The change in entropy for a reversible process, ΔS = Q/T, is a central concept in thermodynamics. It quantifies the dispersal of energy and is used to assess the efficiency of heat engines, refrigerators, and chemical reactions. Engineers apply this equation to design power plants, to optimise refrigerators, and to evaluate the feasibility of processes. In materials science, it guides phase transformation studies. The formula is also essential in environmental engineering for analysing energy conversions. By understanding entropy change, professionals can identify irreversibilities, improve efficiency, and design sustainable energy systems.

  • Design of heat engines and power cycles
  • Refrigeration and air conditioning system analysis
  • Chemical reaction feasibility and equilibrium studies
  • Phase change analysis in materials
  • Energy efficiency and environmental impact assessment

Frequently Asked Questions

Q01What is the formula for entropy change in a reversible process?
A01

For a reversible process at constant temperature, the change in entropy is ΔS = Q_rev / T, where Q_rev is the heat transferred reversibly and T is the absolute temperature. In general, for a reversible path, ΔS = ∫δQ_rev / T.

Q02What is the common mistake when applying this formula?
A02

Applying it directly to an irreversible process. Entropy is a state function, so ΔS for an irreversible process is the same as for a reversible path connecting the same states, but the formula requires using the reversible heat.

Q03What is the unit of entropy?
A03

In SI, the unit is J/K.

Q04How does entropy change in an adiabatic reversible process?
A04

Since Q = 0, ΔS = 0. Such a process is called isentropic.

Q05What is the second law of thermodynamics in terms of entropy?
A05

The entropy of an isolated system never decreases; it either remains constant (reversible) or increases (irreversible).

Q06How is entropy related to the number of microstates?
A06

Boltzmann's entropy formula: S = k_B·ln W. This connects macroscopic entropy to microscopic disorder.

Q07What is the change in entropy when an ideal gas expands isothermally?
A07

For an isothermal expansion from V₁ to V₂, ΔS = nR·ln(V₂/V₁). This is positive for expansion (increase in disorder).

Q08What are the applications of entropy calculations?
A08

  • Determining the direction of spontaneous processes.
  • Design of heat engines and refrigerators.
  • Chemical equilibrium calculations.