Formula & Calculator

Escape Velocity

Escape velocity is the minimum speed you need to completely break free from a planet's or star's gravity without any further push. For Earth, it is about 11.2 km/s (40,000 km/h). For the Moon, it is only 2.4 km/s, which is why the Apollo missions could leave the Moon with a relatively small rocket. If you go slower, you will eventually fall back; if you go faster, you escape forever. It explains why some light gases in our atmosphere leak into space and why black holes are black: their escape velocity exceeds the speed of light.

Astronomy Orbital Mechanics Gravitation
VORZEP · ASTRODYNAMICS & GRAVITATION TOOLS

Escape Velocity Calculator

Compute the escape velocity from a gravitational body using vesc = √(2GM / r). Solve for escape velocity, body mass, or distance from centre. Step-by-step math, a live gravity-well schematic with the escape trajectory, and companion metrics including orbital velocity, surface gravity, and Schwarzschild radius.

vesc = √(2 · G · M / r)
Solve for
Body Mass (M) The mass of the gravitating body in kilograms. The escape velocity depends only on the mass enclosed within the radius r — for a point outside a spherically symmetric body, use the total mass. Typical: Earth = 5.972×10²⁴ kg, Moon = 7.348×10²² kg, Sun = 1.989×10³⁰ kg.
kg
Body mass must be greater than zero.
M = 5.972×10²⁴ kg = 1.000 M⊕ (Earth masses)
Distance from Centre (r) The distance from the centre of the gravitating body to the point where escape velocity is evaluated, in metres. At the surface, r equals the body's radius. Escape velocity decreases as √(1/r), so it is highest at the surface and falls with altitude. Typical: Earth's surface = 6.371×10⁶ m, geostationary orbit = 4.217×10⁷ m.
m
Distance must be greater than zero.
r = 6.371×10⁶ m = 6,371 km
ESCAPE VELOCITY (vesc)
11,186 m/s
v = √(2 × 6.674e-11 × 5.972e24 / 6.371e6) = 11,186 m/s
TERRESTRIAL — EARTH-LIKE ESCAPE VELOCITY
vesc = √(2 · G · M / r)
Step-by-step solution
Escape velocity vs. distance
vesc(r) ∝ 1/√r Current point
Escape velocity vs. mass (at fixed r)
vesc(M) ∝ √M Current point
Sensitivity
Companion gravitational metrics
Gravity well — live schematic
GRAVITY WELL · v_esc = √(2GM/r) BODY M v_esc r v_esc = √(2 × 6.674e-11 × 5.972e24 / 6.371e6) = 11,186 m/s
Gravitational potential well Gravitating body of mass M Escape velocity vector Distance r from centre
What the escape velocity formula really measures
vescescape velocity
=
√(2GM)twice gravitational parameter
÷
√rsqrt of distance

Escape velocity is a speed, not a direction

Contrary to intuition, escape velocity does not require launching straight up. Any object travelling at vesc in any direction — as long as its path does not intersect the body — will escape to infinity, provided no other forces act. This is why orbital launches aim mostly horizontally: reaching vesc horizontally is far more energy-efficient than climbing vertically, since the atmosphere is thin at altitude and the vehicle can use Earth's rotation as a head start.

Escape velocity assumes no further thrust

The formula describes the speed needed to escape using only the kinetic energy an object already has at distance r. A rocket that continues firing its engine can leave the gravitational field at any speed. Similarly, a body moving at less than vesc will follow an elliptical, parabolic, or hyperbolic trajectory depending on its energy — only speeds ≥ vesc lead to escape. At exactly vesc, the trajectory is parabolic and the object reaches infinity with zero residual speed.

Surface escape velocity scales with √(M/R)

For an object of uniform density ρ, mass scales as R³, so escape velocity scales as R√(ρ). This means that for the same density, a larger body has higher escape velocity. Compressing matter to higher density (a white dwarf or neutron star) dramatically increases escape velocity: a neutron star's escape velocity is about 0.6c, and a black hole's escape velocity at its event horizon is exactly c. This is why gravitational redshift and relativistic effects become important for compact objects.

Atmospheric retention depends on vesc

A planet retains a gas if the mean thermal speed of its molecules is much smaller than the escape velocity. Earth's escape velocity is 11.2 km/s while the mean thermal speed of hydrogen at Earth's upper atmosphere is about 2 km/s. Over geological time, the high-energy tail of the Maxwell distribution can still escape, which is why Earth has lost most of its hydrogen and helium. Titan, with escape velocity 2.6 km/s, retains a thick nitrogen atmosphere because nitrogen is heavier and the temperature is lower.

How to Use This Calculator

The escape velocity formula links the body mass, distance from centre, and escape speed. Pick which quantity you want the tool to solve, then fill in the other two.

1. Choose what to solve for

Pick vesc, M, or r from the toggle. The calculator rearranges vesc = √(2GM/r) automatically for whichever you choose.

2. Use realistic presets

Presets cover Solar System bodies: Moon, Mercury, Mars, Earth, Jupiter, and the Sun, with both mass and surface radius values available in the pill rows.

3. Use SI units throughout

Mass in kilograms, distance in metres, velocity in metres per second. G = 6.67430×10⁻¹¹ m³·kg⁻¹·s⁻² is a fundamental constant. The hints show Earth-mass and km/s equivalents.

4. Read the result and verdict

The result card shows escape velocity in m/s plus the km/s equivalent. A colour-coded verdict classifies the body from asteroid-class through terrestrial, Jovian, stellar, and relativistic (near light speed).

5. Check the schematic and charts

The schematic shows a gravity well with the body at the bottom, the escape vector, and the radius. The chart plots vesc vs. distance for the current mass, with the current point highlighted.

6. Switch to Advanced for depth

Advanced mode adds a chart of vesc vs. mass at fixed r, a sensitivity check on a +1% input change, and companion metrics including orbital velocity, surface gravity, Schwarzschild radius, and thermal escape temperature for various gases.

What This Tool Offers

Built around the standard escape-velocity formula vesc = √(2GM/r), the fundamental relationship between mass, distance, and the speed needed to break free of gravity.

Three-way solving

Solve for escape velocity, body mass, or distance from centre. The calculator rearranges the formula for whichever variable you choose.

Live gravity-well schematic

A potential-well diagram with the gravitating body, escape vector, radius marker, and a readout of the full calculation.

Body-class verdict

Each result is classified from asteroid-class through terrestrial, Jovian, stellar, compact, and relativistic (fraction of c) with a coloured badge.

Companion metrics

Orbital velocity, surface gravity, Schwarzschild radius, fraction of light speed, and thermal escape temperature for H₂, He, N₂, and O₂.

Dual comparison charts

Escape velocity vs. distance at fixed mass, plus an advanced escape velocity vs. mass chart at fixed distance.

Reference tables

Solar System escape velocities, atmospheric retention criteria, and a full variable reference table with physical constants.

Reference Tables & Conversions

Escape velocity classes, Solar System data, and gravitational constant reference.

Escape velocity class lookup

km/s
× c
km/s
× c
km/s
× c
km/s
× c
km/s
× c
c = 299,792.458 km/s · Earth v_esc = 11.186 km/s (3.73×10⁻⁵ c) · Sun v_esc = 617.5 km/s (0.206% c)

Solar System Escape Velocities

Surface escape velocity for planets, moons, and the Sun, with companion orbital velocity.

BodyMass (kg)Radius (km)vesc (km/s)vorb (km/s)

Atmospheric Retention Criteria

A planet retains a gas if the escape velocity exceeds about 6× the mean thermal speed of the gas.

Bodyvesc (km/s)Retains H₂?Retains He?Retains N₂?Retains O₂?
Moon2.38NoNoNoNo
Mercury4.25NoNoNoNo
Mars5.03NoNoPartialPartial
Venus10.36NoNoYesYes
Earth11.19NoNoYesYes
Uranus21.3PartialYesYesYes
Neptune23.5PartialYesYesYes
Saturn35.5YesYesYesYes
Jupiter59.5YesYesYesYes
Sun617.5YesYesYesYes

Physical Constants

SymbolNameValueUnits
GGravitational constant6.67430×10⁻¹¹m³·kg⁻¹·s⁻²
cSpeed of light in vacuum2.99792458×10⁸m/s
kBBoltzmann constant1.380649×10⁻²³J/K
mHAtomic mass unit1.66053906660×10⁻²⁷kg
M⊕Earth mass5.972×10²⁴kg
R⊕Earth radius6.371×10⁶m
AUAstronomical unit1.495978707×10¹¹m

Variable Reference

SymbolMeaningTypical rangeUnits
vescEscape velocity10² – 10⁸m/s
GGravitational constant6.67430×10⁻¹¹m³·kg⁻¹·s⁻²
MBody mass10¹⁵ – 10³⁶kg
rDistance from centre10³ – 10¹⁵m
vorbCircular orbital velocityvesc/√2m/s
gSurface gravityGM/r²m/s²

What Does vesc = √(2GM / r) Measure?

Escape velocity is the minimum speed an object must have at a given distance from a gravitating body to escape its gravitational influence entirely — reaching infinity with zero residual speed and no further propulsion. It is a fundamental quantity in orbital mechanics, planetary science, and astrophysics, and it determines everything from the energy required to launch a spacecraft, to which planets retain which gases in their atmospheres, to the size of black holes.

Escape Velocity Formula

The defining relationship is:

vesc = √(2 · G · M / r)

Rearranged to solve for the other two unknowns:

M = vesc² · r / (2G)
r = 2GM / vesc²

The circular orbital velocity at the same distance is vesc / √2:

vorb = √(GM / r) = vesc / √2

The Schwarzschild radius — the radius at which escape velocity equals c — is:

rs = 2GM / c²

Escape Velocity Variables

SymbolMeaningNotes
vescEscape velocityMinimum speed to escape to infinity
GGravitational constant6.67430×10⁻¹¹ m³·kg⁻¹·s⁻²
MBody massMass enclosed within radius r
rDistance from centreRadius at the point of evaluation
vorbCircular orbital velocityvesc / √2 ≈ 0.707 vesc
rsSchwarzschild radius2GM/c², event horizon of a black hole

How Each Variable Affects Escape Velocity

Escape velocity scales with the square root of mass and inversely with the square root of distance. Doubling the body mass increases escape velocity by a factor of √2 ≈ 1.414. Doubling the distance reduces it by the same factor. This inverse-square-root dependence means that escape velocity falls off slowly with altitude — at 4× Earth's radius, escape velocity is still 11.186 / 2 = 5.59 km/s. It only reaches zero at infinity.

The formula assumes the mass M is concentrated within radius r and is spherically symmetric. For a point inside a uniform sphere, only the mass enclosed within r contributes, and the formula must be modified. For most astronomical applications — planets, moons, stars — the surface radius is used, where M is the full body mass.

Escape Velocity Calculation Examples

Given: M = 5.972×10²⁴ kg (Earth), r = 6.371×10⁶ m — solve for vesc
vesc = √(2 × 6.674×10⁻¹¹ × 5.972×10²⁴ / 6.371×10⁶)
vesc = √(7.971×10¹⁴ / 6.371×10⁶) = √(1.251×10⁸)
vesc = 11,186 m/s = 11.186 km/s
Given: vesc = 11,186 m/s, M = 5.972×10²⁴ kg — solve for r
r = 2GM / vesc² = (2 × 6.674×10⁻¹¹ × 5.972×10²⁴) / (11186)²
r = 7.971×10¹⁴ / 1.251×10⁸ = 6.371×10⁶ m = Earth's surface radius
Given: vesc = 617,500 m/s (Sun), r = 6.957×10⁸ m — solve for M
M = vesc² · r / (2G) = (6.175×10⁵)² × 6.957×10⁸ / (2 × 6.674×10⁻¹¹)
M = 1.989×10³⁰ kg = 1 solar mass
Given: vesc = 11,186 m/s — solve for circular orbital velocity
vorb = vesc / √2 = 11,186 / 1.4142 = 7,910 m/s = 7.91 km/s
This is the speed of a low-Earth-orbit satellite.

Frequently Asked Questions

Escape velocity depends only on the gravitating body (through M and r) because the object's own mass cancels out of the energy balance. The kinetic energy needed is ½mv², and the gravitational potential energy to be overcome is GMm/r. Setting them equal: ½mv² = GMm/r, and m cancels, giving v = √(2GM/r). This means a feather and a rocket need the same escape velocity — though in practice the rocket needs far more energy to overcome atmospheric drag and to achieve that speed.

Yes, and many things do. Spacecraft on interplanetary missions exceed Earth's escape velocity by a wide margin — the Voyager probes left the Solar System at about 17 km/s relative to the Sun. What matters is that the object reaches escape velocity at some point with no further propulsion. A rocket that continues to fire its engines can reach infinity at any speed. Conversely, an object moving slower than escape velocity but with continuous thrust can also escape — the formula only applies to ballistic (unpowered) trajectories.

At the event horizon (Schwarzschild radius), the escape velocity equals the speed of light. For a black hole of mass M, rs = 2GM/c². For the Sun's mass, rs ≈ 2.95 km. For Earth's mass, rs ≈ 8.87 mm. Inside the event horizon, escape velocity exceeds c, and no signal — not even light — can escape. This is the defining property of a black hole. The Newtonian formula vesc = √(2GM/r) happens to give the correct Schwarzschild radius when vesc = c, even though a full general-relativistic treatment is required for a rigorous derivation.

A planet retains a gas if its escape velocity is much greater than the mean thermal speed of the gas molecules, which is vth = √(3kBT/m). A useful rule of thumb is that the planet retains the gas if vesc ≥ 6vth. For Earth (vesc = 11.2 km/s), this means hydrogen (vth ≈ 1.9 km/s at 300 K) is only marginally retained, and indeed Earth has lost most of its hydrogen over geological time. Heavier gases like N₂ and O₂ are firmly retained. For the Moon (vesc = 2.4 km/s), even heavy gases escape, which is why the Moon has no atmosphere.

Yes — escape velocity is a scalar magnitude, independent of direction. An object launched horizontally at escape velocity will escape just as surely as one launched vertically, provided it doesn't hit the ground first. In practice, launching horizontally is far more energy-efficient because the vehicle can reach orbital velocity without first climbing out of the atmosphere. This is why real launch vehicles begin pitching over shortly after liftoff, gradually transitioning from vertical to nearly horizontal flight.

Orbital velocity is the speed needed to maintain a circular orbit at distance r: vorb = √(GM/r). Escape velocity is the speed needed to leave the gravitational field entirely: vesc = √(2GM/r). The ratio is always vesc / vorb = √2 ≈ 1.414. So for Earth at the surface, vorb = 7.91 km/s and vesc = 11.19 km/s. The difference in energy is exactly a factor of 2 — escaping requires twice the kinetic energy of orbiting at the same altitude.

Exactly the speed of light, c = 299,792,458 m/s, by definition. The Schwarzschild radius rs = 2GM/c² is the radius at which the Newtonian escape velocity equals c. Inside rs, the Newtonian formula would give vesc > c, which is physically impossible — a signal of the breakdown of Newtonian gravity. A full general-relativistic treatment shows that no timelike or null geodesic can escape from within rs, which is the rigorous statement that a black hole is black.

Calculating...

Variables

Symbol Quantity Unit
v_esc Escape velocity m/s
G Gravitational constant
M Mass of body kg
r Distance from center m

What it means

Escape velocity is the minimum initial speed required for an object to break free from the gravitational influence of a massive body (like a planet or star) without any additional thrust. It is derived from the conservation of energy, balancing kinetic energy against gravitational potential energy. For Earth, v_esc ≈ 11.2 km/s. This concept is essential for launching spacecraft, for understanding planetary atmospheres (gases with molecular speeds exceeding escape velocity are lost), and for studying the formation of celestial bodies. In astrophysics, it determines the size of a black hole’s event horizon (Schwarzschild radius). Understanding escape velocity is critical for astronauts, engineers, and planetary scientists to design missions and to interpret atmospheric evolution.

Worked example

Escape Velocity – Two Detailed Examples

Real‑World
Scenario: A rocket engineer is calculating the minimum speed needed for a spacecraft to escape Earth's gravity without further propulsion. Using Earth's mass (5.972×10²⁴ kg) and radius (6.371×10⁶ m) along with G = 6.67430×10⁻¹¹, they compute the escape velocity. This determines the fuel requirements for the launch vehicle and the trajectory design.
ParameterValue
G (m³/kg·s²)6.67430e-11
M (kg)5.972e24
r (m)6.371e6
1v_esc = √(2 × 6.67430e-11 × 5.972e24 / 6.371e6)
2v_esc ≈ 11,186 m/s ≈ 11.2 km/s
Result 11.2 km/s ✓ Earth escape velocity
Scenario: A planetary scientist is studying the possibility of a moon having an atmosphere. For a moon of mass 7.342×10²² kg and radius 1.737×10⁶ m (similar to our Moon), they compute the escape velocity. If the escape velocity is low, gases can easily escape into space, explaining why the Moon has no atmosphere. This calculation supports their atmospheric loss models.
ParameterValue
G6.67430e-11
M7.342e22
r1.737e6
1v_esc = √(2 × 6.67430e-11 × 7.342e22 / 1.737e6)
2≈ 2.38 km/s (Moon), much lower than Earth
Result 2.38 km/s ✓ Low escape velocity, atmosphere unlikely
Insight: Escape velocity depends on mass and radius. Smaller bodies have lower escape velocities, making it harder to retain an atmosphere.

Common mistakes

  • Escape velocity: The minimum speed to escape a gravitational field.
  • Units: G in m³/(kg·s²), M in kg, r in metres → v in m/s.
  • r: The distance from the centre of the mass – not the surface radius if starting from altitude.
  • Atmospheric effects: Does not account for air resistance – applies to vacuum.
  • Energy conservation: Derived from kinetic = gravitational potential – ensure sign conventions.

Applications

Escape velocity, v_esc = √(2GM/r), is the minimum speed required for an object to break free from the gravitational pull of a celestial body without further propulsion. This concept is critical for space exploration: rockets must reach Earth's escape velocity (about 11.2 km/s) to leave our planet. Astronomers use it to assess whether a planet can retain an atmosphere – if the average molecular speed exceeds escape velocity, the atmosphere will be lost over time. By calculating escape velocity, engineers design launchers and planetary missions. It also helps in understanding the formation of planetary systems. This formula is a cornerstone of astrophysics, relating mass, radius, and gravitational binding.

  • Spacecraft launch and interplanetary mission planning
  • Atmospheric retention and evolution studies (planetary habitability)
  • Determination of black hole event horizons (Schwarzschild radius)
  • Design of gravitational assist manoeuvres
  • Understanding of celestial body mass and size

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  • Published July 8, 2026
  • Last updated October 22, 2026