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Newton's Law of Viscosity

Relates the shear stress in a Newtonian fluid to its viscosity and the local velocity gradient.

Chemical EngineeringFluid MechanicsRheology

Newton's Law of Viscosity Calculatorτ = μ · (dv/dy)

τ (Pa) = μ (Pa·s) × (dv/dy) (s⁻¹)
Select what to solve for — enter the other two values, then click Check
Solve for:
Pa
Pa·s
s⁻¹
Shear Stress (τ)
Low (<10 Pa) Moderate (10–50 Pa) High (50–100 Pa) Very High (>100 Pa)
τ = μ · (dv/dy) · Water viscosity at 20°C ≈ 1.0×10⁻³ Pa·s

Interpretation

Newton's law of viscosity: τ = μ·(dv/dy), relates shear stress to velocity gradient. Defines dynamic viscosity μ. Example: μ=0.001 Pa·s, gradient=100 s⁻¹ → τ=0.1 Pa.

tau = mu * (dv/dy)
Newton's Law of Viscosity

Variables

SymbolQuantityUnit
tauShear stressPa
muDynamic viscosityPa.s
dv/dyVelocity gradient (shear rate)1/s

What it means

Newton’s law of viscosity is the constitutive equation for a Newtonian fluid, which states that the shear stress τ is proportional to the velocity gradient (shear rate) perpendicular to the direction of flow. The proportionality constant is the dynamic viscosity μ. Mathematically, τ = μ (dv/dy). This law applies to fluids like water, air, and most simple liquids. For non‑Newtonian fluids, the relationship is more complex (shear‑thinning, shear‑thickening, etc.). Viscosity is a measure of a fluid’s resistance to deformation. The law is fundamental in fluid mechanics for deriving the Navier‑Stokes equations and for solving problems involving laminar flow in pipes, lubrication, and coating. In engineering, it is used to predict pressure drops and to characterise fluid behaviour. Understanding viscosity is crucial for pump selection, pipeline design, and mixing operations. It also plays a role in food processing, cosmetics, and biomedical applications.

Worked example

Newton's Law of Viscosity – Two Examples

Real‑World
Scenario: Water μ=0.001 Pa·s, dv/dy=500 s⁻¹. Find shear stress τ.
ParameterValue
μ0.001 Pa·s
dv/dy500 s⁻¹
1τ = μ·(dv/dy) = 0.001 × 500 = 0.5 Pa
Result τ = 0.5 Pa ✓ Low stress
Scenario: Oil μ=0.05 Pa·s, dv/dy=100 s⁻¹. Find τ.
ParameterValue
μ0.05
dv/dy100
1τ = 0.05 × 100 = 5.0 Pa
Result τ = 5.0 Pa ✓ Higher stress
Key insight: Shear stress ∝ velocity gradient; viscosity is the proportionality constant.

Common mistakes

  • Viscosity μ: Dynamic viscosity, not kinematic.
  • Velocity gradient dv/dy: Shear rate – in s⁻¹.
  • Shear stress τ: In Pa (N/m²) when SI units are used.
  • Newtonian fluid: This law applies only to Newtonian fluids; non‑Newtonian fluids have a different relationship.
  • Sign convention: Shear stress is positive in the direction of flow.

Applications

Newton's law of viscosity, τ = μ·(dv/dy), defines dynamic viscosity as the ratio of shear stress to velocity gradient. It is the basis for understanding fluid flow behaviour, particularly for Newtonian fluids (where viscosity is constant). Engineers use this relationship to calculate shear stresses in pipes, bearings, and viscometers. It is applied in the design of lubrication systems, coatings, and food processing equipment. The law also underpins the development of non‑Newtonian models (e.g., power‑law, Bingham). By understanding viscosity, professionals can select appropriate pumps, predict pressure drops, and design mixing equipment. It is a fundamental concept in rheology and fluid mechanics.

  • Design of pipeline and channel flow systems
  • Lubrication and tribology analysis in bearings and gears
  • Selection of pumps and mixers based on fluid viscosity
  • Rheological characterisation of fluids (Newtonian vs. non‑Newtonian)
  • Quality control in food, cosmetic, and pharmaceutical industries

Frequently Asked Questions

Q01What is Newton's law of viscosity and what does it describe?
A01

Newton's law of viscosity states that the shear stress in a fluid is proportional to the velocity gradient: τ = μ · (dv/dy), where τ is the shear stress (Pa), μ is the dynamic viscosity (Pa·s), and dv/dy is the velocity gradient (s⁻¹). It defines a Newtonian fluid.

Q02What are the units of viscosity?
A02

In SI, dynamic viscosity μ has units of Pa·s = kg/(m·s). The cgs unit is the poise (1 poise = 0.1 Pa·s). Kinematic viscosity ν = μ/ρ has units of m²/s (Stokes).

Q03What are the common mistakes when using Newton's law?
A03

  • Applying it to non‑Newtonian fluids (e.g., slurries, polymers) where μ is not constant.
  • Using the wrong velocity gradient – it must be the derivative of velocity with respect to the perpendicular direction.
  • Ignoring the temperature dependence of μ.

Q04What is the difference between a Newtonian and a non‑Newtonian fluid?
A04

In a Newtonian fluid, the viscosity is constant at a given temperature. In non‑Newtonian fluids, the apparent viscosity depends on shear rate (e.g., shear‑thinning, shear‑thickening, Bingham plastics).

Q05How does temperature affect viscosity?
A05

For liquids, viscosity decreases with increasing temperature. For gases, viscosity increases with temperature. This is captured by empirical correlations (e.g., Sutherland's law for gases).

Q06What are typical values of viscosity?
A06

  • Water at 20°C: μ ≈ 0.001 Pa·s (1 cP).
  • Air at 20°C: μ ≈ 1.8×10⁻⁵ Pa·s.
  • Motor oil: μ ≈ 0.1‑1 Pa·s.

Q07What is the physical interpretation of viscosity?
A07

Viscosity is a measure of a fluid's resistance to deformation. It arises from intermolecular forces and molecular momentum transfer.

Q08How is viscosity measured?
A08

Common viscometers: capillary (Ubbelohde), rotational (Brookfield), and falling ball. They measure the shear stress vs. shear rate relationship.