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Normal Distribution Probability Density

Calculates the relative likelihood of a continuous random variable taking a specific value under a normal (bell curve) distribution.

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Normal Distribution CalculatorProbability Density Function

f(x) = 1/(σ√(2π)) · e(x−μ)²/(2σ²)
f(x) = density  ·  μ = mean  ·  σ = standard deviation  ·  x = value
⟹ Solvef(x), x, μ, σ
density
value
mean
std dev
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f(x)
f(x): x: μ: σ:
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Normal PDF Curve
PDF curve x location Mean (μ)
f(x) = (1/(σ√(2π))) · e−(x−μ)²/(2σ²)  ·  σ > 0

Interpretation

f(x) = (1/(σ√(2π)))·e^[−(x−μ)²/(2σ²)]. Bell‑shaped density for continuous data. Central to statistics. Used in many natural and social science applications.

f(x) = (1/(σ√(2π))) * e^(-(x-μ)²/(2σ²))
Normal Distribution Probability Density

Variables

SymbolQuantityUnit
f(x)Probability density at x
xValue of interest
μDistribution mean
σDistribution standard deviation

What it means

The normal (Gaussian) distribution is the most important probability distribution in statistics. Its probability density function is symmetrical, bell‑shaped, with parameters μ (mean) and σ (standard deviation). It arises from the central limit theorem and is used to model many natural phenomena (heights, errors, test scores). It is the basis for many statistical tests (z‑tests, t‑tests). The density function gives the probability of a value in an infinitesimal interval. Understanding the normal distribution is essential for inference, confidence intervals, and for many parametric methods. The standard normal (z‑distribution) is a special case with μ=0, σ=1.

Worked example

Normal Distribution PDF – Two Examples

Real‑World
Scenario: IQ scores are normally distributed with μ=100, σ=15. Find the probability density at x=100.
ParameterValue
x100
μ100
σ15
1f(100) = 1/(15√(2π)) × e^(0) = 1/(15×2.5066) = 1/37.599 = 0.0266
Result 0.0266 ✓ Density at mean
Scenario: The same IQ distribution: find f(115).
ParameterValue
x115
μ100
σ15
1z = (115-100)/15 = 1. f(115) = 0.0266 × e^(-0.5) = 0.0266 × 0.6065 = 0.01613
Result 0.01613 ✓ Density at 1σ above mean
Insight: The normal PDF gives the height of the bell curve. The maximum occurs at x=μ. The total area under the curve is 1.

Common mistakes

  • Normal PDF: Probability density function – gives the height of the curve at x, not a probability.
  • Mean μ and standard deviation σ: Parameters of the distribution.
  • Symmetry: The normal distribution is symmetric about μ.
  • Total area: The integral of f(x) over all x equals 1.
  • Units: The density has units of 1/x (e.g., if x is in cm, f(x) has units of 1/cm).

Applications

The normal distribution probability density function describes the classic bell‑shaped curve, characterised by the mean μ and standard deviation σ. It is the most important distribution in statistics, used to model countless natural and engineered phenomena. Engineers use it for process capability analysis, tolerance design, and measurement uncertainty. In quality control, it underlies control charts. In finance, it models asset returns. In research, it is assumed for many parametric tests. By understanding the normal distribution, professionals can compute probabilities, set specification limits, and perform hypothesis tests. Its properties are the basis for many statistical methods, making it essential for anyone working with quantitative data.

  • Process capability analysis and specification setting
  • Measurement uncertainty and error propagation
  • Control charts for statistical process control
  • Financial modelling and risk assessment
  • Parametric hypothesis testing (t‑tests, ANOVA)

Frequently Asked Questions

Q01What is the probability density function (PDF) of a normal distribution?
A01

f(x) = (1/(σ√(2π))) · e^(−(x−μ)²/(2σ²)). It describes the relative likelihood of a continuous random variable taking a specific value, forming the well‑known bell curve.

Q02What is the difference between PDF and probability for continuous variables?
A02

For continuous variables, the PDF is not a probability – it is a density. The actual probability is the area under the curve over an interval (integral). The PDF can exceed 1 for narrow distributions.

Q03What are the parameters μ and σ in the normal PDF?
A03

μ is the mean (centre), and σ is the standard deviation (spread). They completely define the normal distribution.

Q04How is the normal distribution used in statistics?
A04

It is the foundation for many statistical tests (z‑tests, t‑tests, ANOVA, regression), and is used to model natural phenomena, measurement errors, and many more.

Q05What is the standard normal distribution?
A05

The standard normal has μ=0 and σ=1. It is denoted as Z and is obtained by standardising any normal variable: Z = (X−μ)/σ.

Q06How do you compute probabilities from the normal PDF?
A06

You integrate the PDF over a range. Because the integral has no closed form, we use Z‑tables or software to find cumulative probabilities (CDF).

Q07What is the empirical rule for the normal distribution?
A07

About 68% of data lies within ±1σ, 95% within ±2σ, and 99.7% within ±3σ of the mean. This is a quick guide to spread.

Q08How is the normal distribution used in quality control?
A08

Many processes are assumed to be normally distributed. Control charts use this to monitor means and ranges, and to set specification limits.

Q09What is the difference between the normal distribution and the t‑distribution?
A09

The t‑distribution is used when the population standard deviation is unknown and estimated from the sample. It has heavier tails, especially for small sample sizes, to account for extra uncertainty.

Q10What is the central limit theorem and how does it relate to the normal distribution?
A10

The CLT states that the sampling distribution of the sample mean approaches a normal distribution as the sample size increases, regardless of the population distribution (under certain conditions). This justifies many inferential procedures.