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Quadratic Formula

Solves any quadratic equation of the form ax^2 + bx + c = 0 directly from its coefficients.

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Quadratic Formula CalculatorSolve ax² + bx + c = 0

x = (−b ± √(b² − 4ac)) / (2a)
a, b, c = coefficients  ·  x = roots  ·  Discriminant Δ = b² − 4ac
⟹ Solvea, b, c, x
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Δ = —
x₁ = x₂ =
a: b: c:
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x = (−b ± √(b² − 4ac)) / (2a)  ·  If Δ < 0, roots are complex.

Interpretation

x = (−b ± √(b²−4ac))/(2a). Solves ax²+bx+c=0. Finds roots of quadratic equation. Fundamental for algebra and many applications.

x = (-b ± sqrt(b^2 - 4ac)) / (2a)
Quadratic Formula

Variables

SymbolQuantityUnit
a, b, cCoefficients of the quadratic equation
xRoot(s) of the equation

What it means

The quadratic formula gives the solutions (roots) to any quadratic equation ax² + bx + c = 0, where a ≠ 0. The discriminant Δ = b² − 4ac determines the nature of the roots: if Δ > 0, two distinct real roots; if Δ = 0, one repeated real root; if Δ < 0, two complex roots. This formula is indispensable in algebra, physics (projectile motion), engineering (circuit analysis), and many other fields. It is derived by completing the square. Understanding the quadratic formula is a core requirement for high school and college mathematics, and it is one of the most frequently used formulas in problem solving.

Worked example

Quadratic Formula – Two Examples

Real‑World
Scenario: A projectile height h(t)=−5t²+20t+2. Find time to hit ground (h=0).
ParameterValue
a−5
b20
c2
1D = 400 − 4(−5)(2)=440
2t = (−20 ± √440)/(−10) → t≈4.10 s (positive)
Result 4.10 s ✓ Time to ground
Scenario: A rectangle area 50 m², length 3 m longer than width. Solve x(x+3)=50.
ParameterValue
a1
b3
c−50
1x = [−3 ± √(9+200)]/2 = [−3 ± √209]/2 → x≈5.72 m
Result 5.72 m (width) ✓ Length = 8.72 m
Insight: The discriminant determines the nature of roots: D>0 two real, D=0 one, D<0 complex.

Common mistakes

  • Quadratic formula: x = [−b ± √(b² − 4ac)] / (2a) – not just −b/2a.
  • Discriminant: D = b² − 4ac – determines number of real roots.
  • If D > 0: Two distinct real roots; D = 0: one double root; D < 0: two complex roots.
  • Sign: The ± means two possible values – include both.
  • a ≠ 0: If a = 0, the equation is linear – use a different method.

Applications

The quadratic formula, x = (−b ± √(b² − 4ac))/(2a), provides the roots of a quadratic equation ax²+bx+c=0. This is one of the most important algebraic formulas, used to solve a vast array of problems. In physics, it appears in projectile motion and energy conservation. In engineering, it solves for time constants, resonant frequencies, and optimises designs. In finance, it calculates break‑even points. In computer science, it is used in graphics and collision detection. By understanding the discriminant, professionals can determine the nature of solutions (real, repeated, complex). This formula is indispensable in any field that involves polynomial equations.

  • Projectile motion and ballistics calculations
  • Circuit analysis (impedance matching and resonant circuits)
  • Optimisation of quadratic cost functions in economics
  • Root‑finding in computational geometry and ray tracing
  • Stability analysis of second‑order systems

Frequently Asked Questions

Q01What is the quadratic formula and what is it used for?
A01

The quadratic formula solves for the roots of a quadratic equation ax² + bx + c = 0: x = (–b ± √(b² – 4ac)) / (2a). It gives the values of x that satisfy the equation.

Q02What is the common mistake when using the quadratic formula?
A02

Forgetting the plus‑or‑minus sign, which produces only one of the two roots. The ± is essential.

Q03What is the discriminant and what does it tell you?
A03

The discriminant is Δ = b² – 4ac. If Δ > 0, there are two distinct real roots; if Δ = 0, one real root (repeated); if Δ < 0, two complex roots.

Q04What is the sum and product of roots?
A04

For ax² + bx + c = 0, the sum of roots is –b/a, and the product is c/a.

Q05How do you derive the quadratic formula?
A05

By completing the square on ax² + bx + c = 0: divide by a, move the constant, add (b/(2a))², and solve for x.

Q06What are the applications of the quadratic formula?
A06

  • Solving projectile motion equations.
  • Finding intersection points of parabolas.
  • Optimization problems.

Q07What is the vertex of a parabola?
A07

The vertex is at x = –b/(2a). The y‑coordinate is found by substituting this into the equation.

Q08How do you solve a quadratic equation with complex roots?
A08

Use the quadratic formula; the square root of a negative number gives imaginary numbers. For example, x = (–b ± i√(|Δ|))/(2a).

Q09What is the quadratic formula for a = 0?
A09

If a = 0, the equation is not quadratic but linear. The formula is invalid (division by zero).

Q10What is the relationship between the quadratic formula and factoring?
A10

Factoring is an alternative method; the formula works for any quadratic, even when factoring is difficult.