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Specific Orbital Angular Momentum

Angular momentum per unit mass of an orbiting body, conserved throughout an unperturbed orbit.

Orbital MechanicsAstrodynamicsFundamental

Specific Orbital Angular Momentum Calculator

h = r · v · cos(γ)
Solve for h, r, v, or γ
h r, v, γ
m²/s
km
km/s
deg
Solve for:
Result
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Specific Angular Momentum vs. Radius h(r) = r · v · cos(γ)
h(r) for fixed v, γ Computed point
r in km, v in km/s • γ in degrees • h in km²/s

Interpretation

Specific orbital angular momentum: h = r·v·cos(γ), where γ is flight path angle. It is the angular momentum per unit mass. Example: For circular orbit, γ=0, h = r·v.

h = r * v * cos(γ)
Specific Orbital Angular Momentum

Variables

SymbolQuantityUnit
hSpecific angular momentumm2/s
rRadial distancem
vOrbital speedm/s
γFlight path angledeg

What it means

Specific angular momentum is a conserved quantity in central force motion, equal to the cross product of position and velocity. It defines the orbital plane and the shape of the orbit (semi‑latus rectum p = h²/μ). It is used in orbit determination and in the calculation of orbital elements. Understanding h is essential for orbital mechanics and for analysing perturbed orbits.

Worked example

Specific Orbital Angular Momentum – Two Examples

Real‑World
Scenario: Circular orbit r = 6.678×10⁶, v = 7726, flight path angle γ = 0°. Find h.
ParameterValue
r6.678×10⁶
v7726
γ
1h = r·v·cosγ = 6.678e6 × 7726 × 1 = 5.159×10¹⁰ m²/s
Result 5.16×10¹⁰ ✓ LEO
Scenario: r = 4.216×10⁷, v = 3075, γ = 0°. Find h.
ParameterValue
r4.216×10⁷
v3075
1h = 4.216e7 × 3075 = 1.296×10¹¹ m²/s
Result 1.30×10¹¹ ✓ GEO
Key insight: Specific angular momentum is conserved in orbital motion – h = r·v·cosγ.

Common mistakes

  • Specific orbital angular momentum: h = r·v·cos(γ).
  • γ: Flight path angle (angle between velocity and local horizontal).
  • For circular orbit, γ=0, so h = r·v.
  • Units: m²/s.
  • Constant for a given orbit.

Applications

Specific orbital angular momentum, h = r·v·cosγ, is the angular momentum per unit mass, a conserved quantity in central force motion. It determines the shape and orientation of the orbit. Engineers use h to compute the semi‑latus rectum and eccentricity, and to design orbital manoeuvres. It is essential for determining the orbit's geometry and for targeting. By understanding angular momentum, aerospace engineers can predict the path of spacecraft and plan orbit changes with precision.

  • Orbit determination and parameter estimation
  • Trajectory design and targeting
  • Computation of orbital elements from position and velocity
  • Orbital rendezvous and interplanetary navigation
  • Analysis of perturbations and orbital decay

Frequently Asked Questions

Q01What is the Specific Orbital Angular Momentum used for?
A01

It is the angular momentum per unit mass of an orbiting body, conserved throughout an unperturbed orbit. It is used to determine the orbital orientation and eccentricity.

Q02What do the variables h, r, v, and γ represent?
A02

h = specific angular momentum (m²/s)
r = orbital radius (m)
v = orbital speed (m/s)
γ = flight path angle (angle between velocity and local horizontal)

Q03Why is the specific angular momentum important?
A03

It is a constant of the motion for the two‑body problem. It determines the orbital plane and the shape (via the semi‑latus rectum).

Q04What are common mistakes when using this formula?
A04

  • Assuming flight path angle γ = 0 always; it is only zero at perigee/apogee of an elliptical orbit, not generally.
  • Using the wrong units for r and v.
  • Confusing specific angular momentum with total angular momentum.

Q05Give a worked example.
A05

At perigee, r = 7,000 km, v = 8,000 m/s, and γ = 0. h = 7,000,000 × 8000 = 5.6×10¹⁰ m²/s.

Q06How does the specific angular momentum relate to the orbit equation?
A06

The semi‑latus rectum p = h²/μ. The orbit equation is r = p/(1 + e·cos(θ)).

Q07What is the effect of a thrust on angular momentum?
A07

A tangential burn changes the speed without changing the direction, thus changing h.

Q08How do you find the velocity components from h?
A08

At a given radius, the transverse component vθ = h/r, and the radial component vr = √(v² − vθ²).

Q09What is the specific angular momentum of a circular orbit?
A09

For a circular orbit, h = r·v = √(μ·r).

Q10How does the specific angular momentum change with inclination?
A10

It is a vector; the magnitude is invariant, but the vector direction changes with inclination.