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Period of a Simple Pendulum

Calculates the time for one complete swing of a simple pendulum from its length and local gravitational acceleration, valid for small swing angles.

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Period of a Simple Pendulum CalculatorT = 2·π·√(L/g)

T = 2 · π · √( L / g )
T = period (s)  ·  L = length (m)  ·  g = gravitational acceleration (m/s²)
⟹ SolveT, L, g
s
m
m/s²
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Period
T: L: g:
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T = 2·π·√(L/g)  ·  For small angles (θ ≪ 1 rad), period is independent of amplitude.

Interpretation

Period of a simple pendulum: T = 2π√(L/g), where L is length and g is gravity. It depends only on length and gravity, not mass. Example: L=1 m, g=9.81 → T≈2.006 s.

T = 2 * pi * sqrt(L / g)
Period of a Simple Pendulum

Variables

SymbolQuantityUnit
TPeriod of oscillations
LLength of the pendulumm
gGravitational acceleration9.81 m/s2

What it means

The simple pendulum is a classic example of simple harmonic motion. The period T is the time for one complete oscillation. For small amplitudes (sinθ ≈ θ), the period is given by T = 2π√(L/g). This formula shows that the period is independent of the mass and amplitude (for small angles), depending only on the length of the pendulum and the acceleration due to gravity. This makes pendulums useful for clocks and as gravimeters to measure g. In physics, it is a standard experiment to determine g. In engineering, it is used in seismometers and inertial sensors. Understanding this formula is essential for designing time‑keeping devices and for analysing oscillatory systems.

Worked example

Simple Pendulum Period – Two Examples

Real‑World
Scenario: A pendulum has length 1 m. Find its period on Earth (g = 9.81 m/s²).
ParameterValue
L1 m
1T = 2π√(L/g) = 2π√(1/9.81) = 2π × 0.319 = 2.006 s
Result 2.01 s ✓ Standard
Scenario: A pendulum of length 0.5 m. Find its period.
ParameterValue
L0.5 m
1T = 2π√(0.5/9.81) = 2π × 0.226 = 1.42 s
Result 1.42 s ✓ Shorter
Key insight: Pendulum period depends only on length and g – independent of mass.

Common mistakes

  • Small angle approximation: T = 2π√(L/g) is valid only for small amplitudes (θ < ~15°). For larger angles, the period depends on amplitude.
  • Length L: The distance from the pivot to the centre of mass of the bob – not the length of the string if the bob has size.
  • Gravity g: Use local g – varies with altitude and location.
  • Units: L in m, g in m/s² → T in seconds.
  • Damping: This is the ideal simple pendulum; real pendulums have damping (amplitude decays).

Applications

The period of a simple pendulum, T = 2π√(L/g), gives the time for one complete oscillation. It is used in the design of pendulum clocks, seismometers, and gravitational instruments. In engineering, it helps design vibration isolation systems and resonant devices. The formula is also applied in geophysics to measure local gravity variations. In education, it is a classic example of simple harmonic motion. By understanding the pendulum period, engineers can design accurate timekeeping devices, measure gravitational acceleration, and analyse the dynamic response of suspended systems. The simplicity of the formula belies its wide applicability in both scientific research and practical engineering.

  • Design of pendulum clocks and timekeeping devices
  • Seismometers and gravimeters for geophysical surveys
  • Vibration isolation and tuned mass dampers
  • Educational demonstrations of simple harmonic motion
  • Measurement of local gravitational acceleration

Frequently Asked Questions

Q01What is the formula for the period of a simple pendulum?
A01

For small oscillations (θ < 15°), the period is T = 2π·√(L/g), where L is the length of the pendulum (from pivot to centre of mass) and g is the gravitational acceleration. It is independent of the mass and amplitude (for small angles).

Q02What is the common mistake when using this formula?
A02

Applying it to large angles where the small‑angle approximation is invalid. For large amplitudes, the period depends on the initial angle and is longer than T = 2π√(L/g).

Q03What are the assumptions of the simple pendulum formula?
A03

  • The pendulum is a point mass on a massless string.
  • The oscillations are small (< 15°).
  • No air resistance.
  • The pivot is frictionless.

Q04How does the period change with length?
A04

The period is proportional to √L. Doubling the length increases the period by √2 (≈ 1.41).

Q05How does the period change with gravitational acceleration?
A05

The period is inversely proportional to √g. On the Moon (g ≈ 1.62 m/s²), the period is longer than on Earth for the same pendulum.

Q06What is the physical significance of the period?
A06

The period is the time for one complete swing (back and forth). It is used in clocks (pendulum clocks) and in measuring g (gravimeter).

Q07What is the exact period for large amplitudes?
A07

The exact period is given by an elliptic integral: T = 4·√(L/g)·K(k), where k = sin(θ₀/2) and K is the complete elliptic integral of the first kind. This converges to the small‑angle formula as θ₀→0.

Q08How is a simple pendulum used to measure g?
A08

Measure the period T and the length L accurately; then g = 4π²L/T². This is a classic physics experiment.