Home/Physics/Time of Flight (Projectile Motion)

Formula & Calculator

Time of Flight (Projectile Motion)

Calculates the total time a projectile stays in the air before landing at the same height it was launched from.

PhysicsMechanicsDaily Life

Time of Flight CalculatorProjectile Motion

t = 2 · v · sin(θ) / g
t = time of flight  ·  v = initial velocity  ·  θ = launch angle  ·  g = gravitational acceleration
⟹ Solvet, v, θ (g fixed)
m/s
rad
s
m/s²
Please fix the errors above.
Solve for:
Presets:
Time of flight (t)
v: θ: t:
✓ Copied!
Time gauge (seconds)
Short (< 2 s) Medium (2–6 s) Long (> 6 s)
t = 2·v·sin(θ)/g  ·  g = 9.81 m/s² (Earth)  ·  θ measured from horizontal

Interpretation

Time of flight: t = 2v·sin(θ)/g for projectile launched and landing at same height. It is total time in air. Example: v=20 m/s, θ=45° → t = 2×20×0.707/9.81 ≈ 2.88 s.

t = 2 * v * sin(theta) / g
Time of Flight (Projectile Motion)

Variables

SymbolQuantityUnit
tTotal time of flights
vInitial launch speedm/s
thetaLaunch angle above horizontaldegrees
gGravitational acceleration9.81 m/s2

What it means

The time of flight of a projectile is the total duration it remains in the air. For a projectile launched from and landing at the same elevation, t = 2 v sinθ / g. This is derived from the vertical motion equation y = v sinθ t – ½g t², setting y=0. This time determines the range and is used in planning trajectories. In practice, air resistance and varying terrain affect the time. The formula is used in ballistics, sports, and space exploration. Understanding time of flight is essential for timing events and for synchronising actions in projectile motion problems.

Worked example

Time of Flight – Two Examples

Real‑World
Scenario: A ball launched at 20 m/s at 45°. Find its time of flight.
ParameterValue
v20 m/s
θ45°
1t = 2v·sin(θ)/g = 2 × 20 × sin(45°)/9.81 = 40 × 0.707 / 9.81 = 28.28 / 9.81 = 2.88 s
Result 2.88 s ✓ Typical
Scenario: A projectile at 30 m/s at 30°. Find flight time.
ParameterValue
v30 m/s
θ30°
1t = 2 × 30 × sin(30°)/9.81 = 60 × 0.5 / 9.81 = 30 / 9.81 = 3.06 s
Result 3.06 s ✓ Longer
Key insight: Time of flight = 2v·sinθ/g – determined by vertical component of velocity.

Common mistakes

  • Total flight time: For a projectile launched and landing at the same height.
  • Launch angle θ: With horizontal.
  • Initial speed v: Magnitude.
  • Units: v in m/s, g in m/s² → t in s.
  • Neglect air resistance: Real time may be longer if air resistance is significant.

Applications

The time of flight of a projectile, t = 2v sinθ / g, gives the total time the projectile remains in the air. This is essential for timing in sports, for fusing in artillery, and for synchronising events in animations. Engineers use it to design time‑delay mechanisms in pyrotechnics, to calculate the duration of water jet exposure, and to plan sequencing in automated systems. In physics experiments, it helps verify the independence of horizontal and vertical motions. By knowing the time of flight, professionals can coordinate actions that depend on projectile motion, ensuring precision and safety in both recreational and industrial applications.

  • Timing of projectile impacts in sports (baseball, golf)
  • Fuse setting for artillery shells and fireworks
  • Design of automated spraying and coating systems
  • Coordination of high‑speed camera captures
  • Educational verification of kinematic equations

Frequently Asked Questions

Q01What is the time of flight for a projectile launched from ground level?
A01

The total time the projectile is in the air is t = 2·v·sinθ / g. This is the time to return to the same vertical level.

Q02What is the common mistake when using this formula?
A02

Forgetting the factor of 2. The time to reach maximum height is v·sinθ/g; the total flight time is twice that. If launch and landing heights differ, this formula is not valid.

Q03How does the time of flight change with launch angle?
A03

The time is proportional to sinθ. At θ = 90° (vertical launch), it is maximum (t = 2v/g). At θ = 0° (horizontal launch), it is zero (but then it would land immediately).

Q04How does the time of flight change with speed?
A04

Time is proportional to v. Doubling the launch speed doubles the time of flight (for the same angle).

Q05What is the time to reach maximum height?
A05

t_peak = v·sinθ / g. The total flight time is twice that.

Q06How do you calculate the time of flight if the projectile lands at a different height?
A06

Use the quadratic equation: –½gt² + v·sinθ·t + h_0 = 0 (taking upward as positive). Solve for t using the positive root.

Q07Does air resistance affect the time of flight?
A07

Yes, air resistance generally increases the time of flight because it reduces the upward and downward velocities, but the effect depends on the projectile shape and speed.

Q08What is the significance of the time of flight in artillery calculations?
A08

Knowing the time of flight allows gunners to set fuze timers for airburst shells and to predict impact points.