Plug Flow Reactor (PFR) Calculator
Compute the reactor volume for a first-order reaction in a plug flow reactor using V = (FA0 / k) · ln(1 / (1 − X)). Solve for volume, molar flow rate, rate constant, or conversion. Includes step-by-step math, a live PFR schematic with concentration profile, and companion metrics including space time, space velocity, and residence time distribution parameters.
PFR assumes perfect plug flow
In an ideal plug flow reactor, fluid moves through the tube as discrete "plugs" with no axial mixing and no radial gradients. Every element of fluid spends exactly the same time in the reactor, so the concentration decreases continuously along the length. This is the idealization of a well-designed tubular reactor: long and narrow, with turbulent flow and minimal back-mixing. It gives the highest conversion per unit volume of any flow reactor for a given reaction order.
ln(1/(1−X)) grows without bound
The conversion factor ln(1/(1−X)) diverges as X approaches 1. Going from 90% to 99% conversion increases the reactor volume by a factor of 2, but going from 99% to 99.9% increases it by another factor of 1.5 — and so on. This is why industrial reactors rarely push past 99% conversion in a single pass: the incremental volume cost becomes prohibitive. Instead, unreacted material is separated and recycled back to the inlet.
k is strongly temperature-dependent
The rate constant k follows the Arrhenius law: k = A·exp(−Ea/RT). For a typical activation energy of 50–100 kJ/mol, k doubles every 10–15 °C rise in temperature. This makes temperature the most powerful lever for reducing reactor volume, but it comes with trade-offs: higher temperature accelerates unwanted side reactions, may degrade the catalyst, and increases energy costs. Reactor design balances these factors against the required volume.
PFR vs CSTR for first-order
For a first-order reaction, the PFR design equation is VPFR = (FA0/k) · ln(1/(1−X)), while the CSTR design equation is VCSTR = (FA0/k) · X/(1−X). The ratio VCSTR/VPFR grows as X increases: at X = 0.90 it is about 3.9, at X = 0.99 it is about 21, and at X = 0.999 it is about 144. This is why PFRs are strongly preferred for high-conversion first-order reactions — they use dramatically less volume.
How to Use This Calculator
The PFR design equation links the molar flow rate, rate constant, conversion, and reactor volume. Pick what you want to compute, and the calculator solves for the remaining quantity.
1. Choose what to solve for
Pick V, FA0, k, or X from the toggle. The calculator rearranges V = (FA0/k)·ln(1/(1−X)) for whichever variable you choose.
2. Use realistic presets
Presets cover industrial and lab ranges: FA0 from 0.01 to 1,000 mol/s, k from 0.001 to 100 s⁻¹, and X from 50% to 99.9%.
3. Use SI units consistently
Molar flow rate in mol/s, rate constant in s⁻¹ (liquid-phase first-order), and volume in m³. Hints show mol/h and half-life for context.
4. Read the result and verdict
The result card shows reactor volume in m³ plus the full calculation. A colour-coded verdict classifies the reactor scale from lab-scale through pilot, industrial, and very large.
5. Check the schematic and charts
The schematic shows the PFR tube with inlet/outlet streams, plug-flow arrows, and the concentration profile. The chart plots conversion vs. volume and the axial concentration profile.
6. Switch to Advanced for depth
Advanced mode adds a concentration-profile chart, a sensitivity check on +1% input changes, and companion metrics including space time, space velocity, CSTR comparison, PFR/CSTR volume ratio, and residence time.
What This Tool Offers
Built around the standard PFR design equation for first-order reactions: V = (FA0/k) · ln(1/(1−X)).
Four-way solving
Solve for volume, molar flow rate, rate constant, or conversion. The calculator rearranges the formula for whichever variable you choose.
Live PFR schematic
A tubular reactor diagram with plug-flow arrows, inlet/outlet streams, concentration profile curve, and readout of the full calculation.
Reactor-scale verdict
Each result is classified from lab-scale through pilot, industrial, and very large, based on the computed volume.
Companion reactor metrics
Space time τ, space velocity SV, CSTR equivalent volume, PFR/CSTR ratio, residence time, and volumetric flow rate.
Dual comparison charts
Conversion vs. reactor volume, plus an advanced axial concentration profile along the reactor length.
Reference tables
Conversion-volume lookup, PFR vs CSTR comparison, and a full variable reference table with physical constants.
Reference Tables & Conversions
Reactor volume scales, PFR vs CSTR comparison, and PFR design reference.
PFR design equation lookup (FA0 = 1 mol/s, k = 0.1 s⁻¹)
PFR vs CSTR Volume Comparison (First-Order)
For the same FA0 and k, a CSTR requires more volume than a PFR for high conversions.
| Conversion X | VPFR (m³) | VCSTR (m³) | VCSTR / VPFR |
|---|
Typical Rate Constants for First-Order Reactions
Representative values of k at 25 °C for common liquid-phase first-order reactions.
| Reaction | k (s⁻¹) | Half-life | Notes |
|---|---|---|---|
| Decomposition of N₂O₅ | 3.4×10⁻⁵ | 5.6 h | Gas-phase, at 25 °C |
| Hydrolysis of sucrose | 2.1×10⁻⁶ | 91 h | Acid-catalyzed, at 25 °C |
| Radioactive decay (¹⁴C) | 3.8×10⁻¹² | 5,730 yr | Used in archaeology |
| Decomposition of H₂O₂ (catalyzed) | 1.0×10⁻³ | 11.6 min | With catalase enzyme |
| Cis-trans isomerization | 1.0×10⁻² | 69 s | Photoisomerization |
| Enzyme-catalyzed reaction | 10² – 10⁶ | < 1 ms | Turnover numbers of enzymes |
| Free-radical polymerization initiation | 10⁻⁶ – 10⁻⁴ | hours | Initiator decomposition |
| Industrial esterification | 10⁻⁵ – 10⁻³ | minutes to hours | Typically acid-catalyzed |
Variable Reference
| Symbol | Meaning | Typical range | Units |
|---|---|---|---|
| V | Reactor volume | 10⁻⁶ – 10³ | m³ |
| FA0 | Inlet molar flow rate of A | 10⁻⁴ – 10³ | mol/s |
| k | First-order rate constant | 10⁻⁶ – 10² | s⁻¹ |
| X | Fractional conversion | 0.5 – 0.999 | — |
| τ | Space time | V / v0 | s |
| SV | Space velocity | 1 / τ | s⁻¹ |
| CA0 | Inlet concentration | 1 – 10⁴ | mol/m³ |
What Does V = (FA0 / k) · ln(1 / (1 − X)) Measure?
This equation gives the volume required in an ideal plug flow reactor to achieve a specified fractional conversion of a reactant undergoing a first-order reaction. It is the fundamental design equation for tubular reactors in chemical engineering, used to size reactors for petrochemical processing, pharmaceutical synthesis, wastewater treatment, and polymer production. Given an inlet molar flow rate, a reaction rate constant, and a target conversion, it tells you exactly how much reactor volume you need — the first question in any reactor design problem.
PFR Design Equation for First-Order Reactions
The defining relationship is:
Rearranged to solve for the other three quantities:
k = FA0 · ln( 1 / (1 − X) ) / V
X = 1 − exp( −k · V / FA0 )
Equivalently, in terms of concentration and volumetric flow rate (CA0 = FA0 / v0, τ = V / v0):
where τ is the space time. The CSTR design equation for the same reaction is:
PFR Variables
| Symbol | Meaning | Notes |
|---|---|---|
| V | Reactor volume | Volume of the reactor tube in m³ |
| FA0 | Inlet molar flow rate | mol/s of limiting reactant A |
| k | First-order rate constant | s⁻¹, temperature-dependent via Arrhenius |
| X | Fractional conversion | 0 to 1; dimensionless |
| τ | Space time | V / v0, in seconds |
| v0 | Volumetric flow rate | m³/s at inlet conditions |
| CA0 | Inlet concentration | mol/m³ = FA0 / v0 |
How Each Variable Affects Reactor Volume
Reactor volume scales linearly with molar flow rate and inversely with the rate constant, so doubling the throughput requires doubling the volume at constant conversion, while doubling k halves it. The conversion dependence is logarithmic and much steeper: going from 90% to 99% conversion more than doubles the required volume, and from 99% to 99.9% multiplies it again by about 1.5. This logarithmic penalty is why industry rarely pushes single-pass conversion beyond 99% — it is usually more economical to separate and recycle unreacted material.
The rate constant k depends strongly on temperature via the Arrhenius equation. For a typical activation energy, raising the temperature by 10 °C roughly doubles k, which halves the required reactor volume at the same conversion. This is why industrial reactors often run at elevated temperatures — but there are limits: unwanted side reactions accelerate too, catalysts may sinter or deactivate, and materials of construction may not withstand extreme temperatures. Optimizing the trade-off between reactor volume, temperature, and selectivity is a central problem in chemical reaction engineering.
PFR Calculation Examples
V = (1 / 0.1) · ln( 1 / (1 − 0.95) )
V = 10 · ln(20) = 10 · 2.9957
V = 29.96 m³
FA0 = V · k / ln(1/(1−X)) = 30 · 0.1 / 2.9957
FA0 = 1.001 mol/s
k = FA0 · ln(1/(1−X)) / V = 1 · 2.9957 / 30
k = 0.09986 s⁻¹
X = 1 − exp( −k · V / FA0 ) = 1 − exp(−0.1 · 30 / 1)
X = 1 − exp(−3) = 1 − 0.0498 = 0.9502 (95.02%)
Frequently Asked Questions
An ideal plug flow reactor (PFR) is a tubular reactor in which fluid flows as discrete "plugs" with no axial mixing and no radial concentration or temperature gradients. Every fluid element that enters at time t exits at time t + τ, where τ = V / v₀ is the residence time. This means every element experiences exactly the same reaction history, which gives the PFR its characteristic design equation. Real tubular reactors approximate ideal PFR behavior when the length-to-diameter ratio is large (typically >50), the flow is turbulent (Reynolds > 10,000), and there are no significant radial gradients or back-mixing.
The term ln(1/(1−X)) comes from integrating the first-order rate law dCA/dz = −k·CA/v₀ along the reactor length. Because the reaction rate is proportional to concentration, as reactant is consumed the rate slows down. The last few percent of conversion require progressively more volume because the driving force (concentration of A) is almost gone. At X = 0.5, the term equals 0.693. At X = 0.9, it is 2.303. At X = 0.99, it is 4.605. At X = 0.999, it is 6.908. So going from 90% to 99% conversion doubles the reactor volume, and 99% to 99.9% adds another 50% — even though the incremental conversion is only 0.9 percentage points.
For first-order reactions, PFRs always require less volume than CSTRs at the same conversion, and the advantage grows with conversion. At X = 0.5, the PFR is about 1.4× smaller; at X = 0.9, about 3.9× smaller; at X = 0.99, about 21× smaller. So PFRs are preferred when high conversion is required, when the reaction is fast, and when continuous operation is feasible. CSTRs are preferred when you need tight temperature control (a CSTR operates at uniform conditions), when the reaction has a sharp optimum temperature, or when the feed contains solids or is prone to fouling (CSTRs are easier to clean). For autocatalytic reactions, a CSTR followed by a PFR often gives the smallest total volume.
Temperature enters through the rate constant k, which follows the Arrhenius equation: k = A·exp(−Ea/RT). Higher temperature means larger k, which means less reactor volume for the same conversion. For a typical activation energy of 70 kJ/mol, raising the temperature from 300 K to 310 K increases k by a factor of about 2.3, and thus reduces the required volume by the same factor. This is why industrial reactors often run at high temperature. The limits are side reactions (which may have different activation energies and become more prominent at high T), catalyst stability, and materials of construction.
Space time τ = V / v₀ is the reactor volume divided by the inlet volumetric flow rate, expressed in seconds (or sometimes hours). For a first-order reaction in an ideal PFR, τ = (1/k) · ln(1/(1−X)). Space time is a measure of how long, on average, a fluid element resides in the reactor. Its reciprocal is space velocity SV = 1/τ, which tells you how many reactor volumes of feed are processed per unit time. For industrial processes, SV is often quoted in h⁻¹: SV = 2 h⁻¹ means the reactor processes two reactor volumes per hour.
Yes. The equation V = (FA0/k)·ln(1/(1−X)) assumes constant volumetric flow rate, which is valid for liquid-phase reactions or for gas-phase reactions with no change in total moles. For gas-phase reactions with changing total moles (e.g., A → 2B), the volumetric flow rate changes as conversion proceeds, and the design equation must be modified. For the reaction A → products with ε = change in moles per mole of A reacted, the design equation becomes: V = (FA0/k) · ∫0X dX / [(1−X)(1+εX)]. This integral is evaluated analytically or numerically depending on ε. Advanced reactor design software handles these cases automatically.
For a first-order reaction, k has units of reciprocal time — s⁻¹ in SI, or min⁻¹, h⁻¹, or day⁻¹ in other conventions. The design equation V = (FA0/k)·ln(1/(1−X)) requires k in s⁻¹ if FA0 is in mol/s and V is to be in m³ (mol·s⁻¹ / s⁻¹ = mol). If you use k in min⁻¹, then FA0 must be in mol/min for V in m³. Whatever time unit you choose for k, use the same for FA0. The hint under the k field shows the half-life t1/2 = ln(2)/k for reference — a useful sanity check on whether the value is physically reasonable.
Variables
| Symbol | Quantity | Unit |
|---|---|---|
| V | Reactor volume | m3 |
| F_A0 | Molar feed rate of reactant A | mol/s |
| k | First-order rate constant | 1/s |
| X | Target fractional conversion |
What it means
For an isothermal plug flow reactor (PFR) with a first‑order reaction A → products, the design equation gives the reactor volume V required to achieve a conversion X. The equation is V = (F_A0 / k) ln(1/(1 − X)), where F_A0 is the inlet molar flow of A, k is the rate constant, and X is the conversion. This expression is derived from the mole balance and the rate law. It shows that as conversion approaches 1, the required volume goes to infinity because the reaction rate becomes very slow at low concentrations. In practice, PFRs are used for high‑throughput, continuous production. The equation is also applicable to other reaction orders with different integral forms. It is essential for sizing tubular reactors, which are common in the petrochemical and polymer industries. Understanding the design equation for PFRs is a core competency in chemical reaction engineering.
Worked example
PFR Volume – Two Examples
Real‑World| Parameter | Value |
|---|---|
| F_A0 | 10 mol/s |
| k | 0.1 s⁻¹ |
| X | 0.8 |
| Parameter | Value |
|---|---|
| F_A0 | 5 |
| k | 0.05 |
| X | 0.9 |
Common mistakes
- First‑order reaction: The rate law must be −r_A = k C_A. If the order is different, the integral changes.
- Constant density: This equation assumes constant volumetric flow (ρ constant). For gas‑phase with pressure drop, adjust.
- Molar flow F_A0: Inlet molar flow of reactant A, in mol/s or kmol/h – consistent with k and V.
- Rate constant k: Units depend on reaction order; for first order, s⁻¹ (if using C in mol/m³).
- Conversion X: Must be between 0 and 1; at X=1, volume is infinite.
Applications
The design equation for a plug flow reactor (PFR) with first‑order reaction is V = (F_A0 / k) · ln(1/(1−X)). This relationship allows engineers to calculate the required reactor volume for a given conversion, or the conversion achievable with a given volume. PFRs are characterised by no axial mixing and are often used for fast reactions and high‑temperature processes. This equation assumes constant density and isothermal operation. Engineers apply it to design tubular reactors, catalytic cracking units, and polymerisation systems. By understanding the PFR equation, professionals can optimise reactor dimensions, select appropriate operating conditions, and integrate reactors with other process units to achieve overall process objectives.
- Design of tubular reactors for gas‑phase and liquid‑phase reactions
- Sizing of catalytic reactors (e.g., ammonia synthesis, cracking)
- Optimisation of reaction conversion with respect to volume and temperature
- Scale‑up of PFRs from laboratory data
- Comparison with CSTR performance for given kinetics
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