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Photon Momentum

Calculates the momentum carried by a single photon, despite having zero rest mass, from its wavelength.

OpticsPhotonicsFundamental

Photon Momentum CalculatorQuantum Mechanics · de Broglie

p = h / λ
p = photon momentum  ·  h = Planck constant  ·  λ = wavelength
⟹ Solvep, h, λ
kg·m/s
J·s
m
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Photon Momentum (p) Gauge
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p = h / λ  ·  h = 6.62607015 × 10⁻³⁴ J·s  ·  All quantities in SI units

Interpretation

p = h/λ. Momentum of a photon. Used in radiation pressure, Compton scattering, and gravitational lensing.

p = h/λ
Photon Momentum

Variables

SymbolQuantityUnit
pPhoton momentumkg*m/s
hPlanck's constantJ*s
λWavelengthm

What it means

A photon has momentum inversely proportional to its wavelength. This is used to explain radiation pressure (solar sails), the Compton effect, and gravitational lensing (light bending due to gravity). Understanding this is essential for quantum mechanics and for applications like laser cooling and trapping of atoms. The formula is derived from the de Broglie relation and Planck’s law.

Worked example

Photon Momentum – Two Detailed Examples

Real‑World
Scenario: A photon of wavelength λ = 400 nm carries momentum p = h/λ = 6.626e-34 / 400e-9 = 1.6565e-27 kg·m/s. This momentum is extremely small, but it can be transferred to atoms in optical tweezers, where the momentum transfer is used to trap and manipulate particles. The physicist uses this in designing laser cooling experiments.
ParameterValue
λ (nm)400
1p = 6.626e-34 / 400e-9 = 1.6565e-27 kg·m/s
Result 1.66×10⁻²⁷ kg·m/s ✓ Photon momentum
Scenario: A 500 nm photon has momentum p = 6.626e-34 / 500e-9 = 1.325e-27 kg·m/s. In a solar sail, the momentum transfer from sunlight can produce a small but continuous thrust. The engineer uses this to estimate the force on a sail, which is crucial for interstellar propulsion concepts.
ParameterValue
λ500
1p = 6.626e-34 / 500e-9 = 1.325e-27 kg·m/s
Result 1.33×10⁻²⁷ kg·m/s ✓ Momentum
Insight: Photon momentum is inversely proportional to wavelength. Although individually tiny, the collective momentum of many photons can be significant, as in radiation pressure and laser propulsion.

Common mistakes

  • Photon momentum: p = h / λ – the momentum of a photon.
  • Units: h in J·s, λ in m → p in kg·m/s.
  • Alternatively: p = E / c – consistent with relativity.
  • Radiation pressure: Light exerts pressure due to photon momentum – pressure = intensity / c for absorbing surfaces.
  • Quantum mechanics: Photons have momentum despite having zero rest mass.

Applications

Photon momentum, p = h/λ, describes the momentum of a photon as inversely proportional to its wavelength. This concept is key in understanding radiation pressure, laser cooling, and atomic physics. Engineers use it in designing optical tweezers, in spacecraft solar sails, and in atom interferometry. By calculating photon momentum, they can predict the force exerted by light on particles. This is also used in quantum optics for understanding the recoil effect in absorption and emission. Understanding photon momentum is essential for advanced photonics and quantum technology applications.

  • Optical trapping and tweezers for manipulating particles
  • Solar sail propulsion for spacecraft
  • Laser cooling and trapping of atoms
  • Quantum optics and atom interferometry
  • Education on the dual nature of light

Frequently Asked Questions

Q01What is the Photon Momentum formula used for?
A01

It calculates the momentum carried by a photon, despite its zero rest mass: p = h / λ.

Q02What do the variables p, h, and λ represent?
A02

p = photon momentum (kg·m/s).
h = Planck's constant.
λ = wavelength.

Q03How is photon momentum derived?
A03

From the de Broglie relation p = h/λ, which applies to all quantum particles, including massless photons.

Q04What is the relationship between photon momentum and energy?
A04

For a photon, E = pc, since E = hc/λ and p = h/λ.

Q05What is the significance of photon momentum?
A05

It explains radiation pressure, the photoelectric effect (momentum transfer), and the Compton effect.

Q06Give a worked example using the photon momentum formula.
A06

For λ = 500 nm, p = 6.626×10⁻³⁴ / (500×10⁻⁹) = 1.325×10⁻²⁷ kg·m/s.

Q07What are the common pitfalls when applying the photon momentum formula?
A07

  • Assuming photon momentum requires mass; it comes from the wave nature.
  • Confusing momentum with energy.
  • Using the wrong units for λ.

Q08How does photon momentum relate to radiation pressure?
A08

When a photon is absorbed or reflected, its momentum changes, exerting a force on the surface.

Q09What is the Compton effect and how does it involve photon momentum?
A09

In Compton scattering, a photon transfers momentum and energy to an electron, resulting in a wavelength shift.

Q10How is photon momentum used in laser cooling?
A10

Momentum transfer from photons to atoms can slow down atoms, cooling them to very low temperatures.