Formula & Calculator

Raoult's Law

Predicts the partial vapor pressure of a component in an ideal liquid mixture from its mole fraction and pure-component vapor pressure.

Chemical EngineeringThermodynamicsSeparation Processes

Raoult's Law CalculatorPi = xi · Pisat

Pi = xi × Pisat
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Pi = xi · Pisat · Ideal solution assumption

Interpretation

Raoult's law: P_i = x_i · P_i_sat for ideal mixtures. Partial pressure is proportional to liquid mole fraction. Example: x=0.5, P_sat=100 kPa → P_i=50 kPa.

P_i = x_i * P_i_sat
Raoult's Law

Variables

SymbolQuantityUnit
P_iPartial pressure of component ikPa
x_iLiquid mole fraction of component i
P_i_satPure-component vapor pressure at system temperaturekPa

What it means

Raoult’s law describes the vapour‑liquid equilibrium for ideal mixtures. It states that the partial pressure of component i in the vapour phase is equal to the product of its liquid mole fraction x_i and the vapour pressure of the pure component at the same temperature, P_i_sat. This law applies when the liquid solution is ideal (intermolecular forces are similar) and the vapour behaves as an ideal gas. It is the foundation of distillation calculations, as it relates composition to temperature and pressure. For non‑ideal mixtures, Raoult’s law is modified with activity coefficients. Raoult’s law is used to generate T‑x‑y diagrams, to calculate bubble and dew points, and to design distillation columns. It is also applied in environmental engineering to estimate the partitioning of volatile organic compounds between air and water. Though idealisation, it provides a good starting point for many separation processes.

Worked example

Raoult's Law – Two Examples

Real‑World
Scenario: Mole fraction xᵢ = 0.4, pure vapour pressure Pᵢ_sat = 101.3 kPa. Find partial pressure Pᵢ.
ParameterValue
xᵢ0.4
Pᵢ_sat101.3 kPa
1Pᵢ = xᵢ × Pᵢ_sat = 0.4 × 101.3 = 40.52 kPa
Result Pᵢ ≈ 40.5 kPa ✓ Ideal
Scenario: xᵢ = 0.6, Pᵢ_sat = 50 kPa. Find Pᵢ.
ParameterValue
xᵢ0.6
Pᵢ_sat50 kPa
1Pᵢ = 0.6 × 50 = 30 kPa
Result Pᵢ = 30 kPa ✓ Linear
Key insight: Raoult's law states partial pressure ∝ mole fraction for ideal solutions.

Common mistakes

  • Ideal solution: Raoult’s law applies only to ideal mixtures; for non‑ideal, use activity coefficients.
  • Vapour pressure P_i_sat: At the system temperature, often from Antoine or other correlations.
  • Mole fraction x_i: In the liquid phase, dimensionless.
  • Partial pressure P_i: In the same units as P_i_sat.
  • Total pressure: If the vapour is ideal, P_total = sum(P_i).

Applications

Raoult's law, P_i = x_i·P_i_sat, describes the vapour‑liquid equilibrium for ideal mixtures, where the partial pressure of each component is proportional to its liquid mole fraction and its pure‑component vapour pressure. This law is the foundation of distillation calculations, flash separations, and condensation processes. Engineers use it to estimate bubble and dew points, to determine relative volatility, and to design distillation columns. Although ideal mixtures are rare, Raoult's law provides a useful first approximation and is the basis for more advanced activity coefficient models. It is also applied in environmental engineering to estimate the fate of volatile organic compounds. By applying this law, professionals can predict phase behaviour and design separation units effectively.

  • Bubble‑point and dew‑point calculations for distillation
  • Design of flash separators and partial condensers
  • Estimation of relative volatility for distillation column design
  • Environmental assessment of volatile chemical emissions
  • Base case for activity coefficient models (e.g., Wilson, NRTL)

Frequently Asked Questions

Q01What is Raoult's law and what does it predict?
A01

Raoult's law states that the partial vapor pressure of a component in an ideal liquid mixture is equal to the product of its mole fraction in the liquid (x_i) and its vapor pressure as a pure component (P_i^sat): P_i = x_i · P_i^sat. It applies to ideal solutions and is the basis for simple distillation calculations.

Q02What are the assumptions of Raoult's law?
A02

  • Liquid solution is ideal (no interactions between components).
  • Vapour phase behaves as an ideal gas.
  • Temperature is constant.
These assumptions are valid for similar molecules and at moderate pressures.

Q03What are the common mistakes when using Raoult's law?
A03

  • Applying it to strongly non‑ideal mixtures without activity coefficients.
  • Using it for components with very different molecular sizes or polarities.
  • Forgetting that the total pressure is the sum of partial pressures (Dalton's law).
  • Using the wrong vapor pressure (e.g., at a different temperature).

Q04How do you use Raoult's law to construct a T‑xy diagram?
A04

For a binary mixture, the bubble point temperature is found by solving P = x_A·P_A^sat(T) + x_B·P_B^sat(T) for T. Then the vapour composition is y_A = x_A·P_A^sat(T)/P. This gives the equilibrium curve.

Q05What is the difference between Raoult's law and Henry's law?
A05

Raoult's law applies to the solvent (major component) and is based on mole fraction. Henry's law applies to solutes at low concentrations and uses a Henry constant: P_i = H·x_i. Both are limiting laws; Raoult's law is valid as x_i → 1, Henry's law as x_i → 0.

Q06What is an ideal solution and how does Raoult's law define it?
A06

An ideal solution is one where the interactions between unlike molecules are the same as between like molecules. Raoult's law is the defining equation for ideal solutions. Real solutions show positive or negative deviations.

Q07How do you handle deviations from Raoult's law?
A07

Use activity coefficients (γ_i): P_i = γ_i·x_i·P_i^sat. γ_i is obtained from excess Gibbs free energy models (e.g., Wilson, NRTL).

Q08What are the applications of Raoult's law?
A08

  • Distillation column design.
  • Flash calculations.
  • Vapor‑liquid equilibrium (VLE) data generation.
  • Environmental fate modelling.