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Self-Inductance EMF

Calculates the electromotive force induced in an inductor due to a changing current through itself, based on its inductance.

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Self‑Inductance EMF CalculatorFaraday’s Law · Inductors

EMF = L · dI/dt
EMF = induced voltage  ·  L = inductance  ·  dI/dt = rate of current change
⟹ SolveEMF, L, dI/dt
V
H
A/s
Please fix the errors above.
Solve for:
Presets:
EMF (ε)
ε: L: dI/dt:
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Current Rate (dI/dt) Gauge
Slow (< 1 A/s) Moderate (1–10 A/s) Fast (> 10 A/s)
ε = L · (dI/dt)  ·  Inductance in henries (H), current rate in amperes per second (A/s)

Interpretation

Self‑inductance EMF: EMF = –L·(ΔI/Δt), where L is inductance, ΔI/Δt is rate of change of current. It opposes changes in current. Example: L=2 H, current changes at 3 A/s → EMF = –6 V.

EMF = -L * (delta_I / delta_t)
Self-Inductance EMF

Variables

SymbolQuantityUnit
EMFInduced electromotive forceV
LInductance of the coilH
delta_IChange in currentA
delta_tTime interval over which the current changess

What it means

Self‑inductance is the property of a circuit (often a coil) by which a change in current induces an EMF that opposes the change. The EMF is given by EMF = –L (dI/dt), where L is the inductance in henries. This is a manifestation of Faraday’s law applied to a single circuit. Inductance depends on the geometry and the magnetic permeability of the medium. Inductors are used in filters, transformers, and energy storage (in switching power supplies). The opposition to change in current is responsible for the time constant in RL circuits. Understanding self‑inductance is crucial for analysing transient behaviour in circuits and for designing inductive components.

Worked example

Self-Inductance EMF – Two Examples

Real‑World
Scenario: An inductor L = 0.1 H has a current change of 2 A in 0.01 s. Find the self-induced EMF.
ParameterValue
L0.1 H
ΔI2 A
Δt0.01 s
1EMF = -L·ΔI/Δt = -0.1 × 2/0.01 = -20 V
Result 20 V ✓ Significant
Scenario: L = 0.5 H, ΔI = 1 A, Δt = 0.05 s. Find EMF.
ParameterValue
L0.5 H
ΔI1 A
Δt0.05 s
1EMF = -0.5 × 1/0.05 = -10 V
Result 10 V ✓ Moderate
Key insight: Self-induced EMF opposes the change in current – Lenz's law explains it.

Common mistakes

  • Self‑inductance L: In henries (H) – depends on geometry and core material.
  • Current change ΔI: Change in current over time – sign matters.
  • Time interval Δt: In seconds.
  • Negative sign: Indicates the induced EMF opposes the change in current (Lenz’s law).
  • No changing current: If current is steady, EMF = 0.

Applications

Self‑inductance EMF, EMF = −L·ΔI/Δt, describes the voltage induced in an inductor when the current changes. This formula is essential for designing inductors, transformers, and switching power supplies. Engineers use it to model circuits with inductive components, to suppress voltage spikes in relay and motor drives, and to design chokes and filters. In power electronics, it helps design boost converters and flyback transformers. The principle also underlies the operation of ignition coils in cars. By understanding self‑inductance, professionals can design reliable and efficient electrical circuits that manage inductive energy safely.

  • Design of inductors for power supplies and filters
  • Snubber circuits and transient suppression
  • Automotive ignition systems and ignition coils
  • Boost and buck converter design
  • Electromagnetic compatibility and noise reduction

Frequently Asked Questions

Q01What is the EMF induced by self‑inductance?
A01

When the current through an inductor changes, it induces an EMF that opposes the change: EMF = –L·dI/dt, where L is the self‑inductance (in henries, H). This is the basis for inductors in circuits.

Q02What is the common mistake when applying this formula?
A02

Confusing self‑inductance with mutual inductance. Self‑inductance refers to the EMF induced in the same coil by its own current change; mutual inductance refers to the EMF induced in a separate coil.

Q03What is the unit of inductance?
A03

The henry (H) = V·s/A.

Q04How does an inductor behave in a DC circuit?
A04

In steady DC, dI/dt = 0, so the EMF is zero, and the inductor acts as a short circuit (ideal case). However, during transients (e.g., switching on/off), it opposes current changes.

Q05What is the energy stored in an inductor?
A05

The energy stored in the magnetic field of an inductor is U = ½L·I². This is analogous to the energy stored in a capacitor (½CV²).

Q06How is self‑inductance calculated for a solenoid?
A06

For a long solenoid of N turns, length l, cross‑sectional area A, L = μ₀·N²·A/l. For a coil with a magnetic core, multiply by the relative permeability.

Q07What is the difference between self‑inductance and inductance?
A07

They are essentially the same; inductance often refers to self‑inductance. Mutual inductance is a separate parameter.

Q08What is the time constant of an RL circuit?
A08

The time constant τ = L/R. It is the time for the current to reach about 63% of its final value after a voltage is applied.