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de Broglie Wavelength

Calculates the wavelength associated with any moving particle based on its momentum, reflecting the wave-particle duality of matter.

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de Broglie Wavelength Calculatorλ = h / p

λ = h / p
λ = wavelength (m)  ·  h = Planck's constant (J·s)  ·  p = momentum (kg·m/s)
⟹ Solveλ, h, p
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J·s
kg·m/s
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λ = h / p  ·  The de Broglie wavelength of a particle relates its wave-like properties to its momentum.

Interpretation

de Broglie wavelength: λ = h/p, where h is Planck's constant, p is momentum. It shows wave‑particle duality: particles have wavelength. Example: Electron with momentum 1e-24 kg·m/s → λ = 6.63e-34/1e-24 = 6.63e-10 m.

lambda = h / p
de Broglie Wavelength

Variables

SymbolQuantityUnit
lambdade Broglie wavelengthm
hPlanck's constant6.626e-34 J.s
pMomentum of the particlekg.m/s

What it means

The de Broglie wavelength is the wavelength associated with a moving particle, demonstrating that matter has wave‑like properties. The formula λ = h/p relates the wavelength to momentum. This concept is central to quantum mechanics and explains phenomena like electron diffraction and the quantization of atomic orbits. It is used in electron microscopy, where electrons are used to image objects at atomic scale. The de Broglie wavelength also appears in the Heisenberg uncertainty principle and in the development of wave mechanics. Understanding this duality is fundamental to modern physics.

Worked example

de Broglie Wavelength – Two Examples

Real‑World
Scenario: An electron has momentum p = 1×10⁻²⁴ kg·m/s. Find its de Broglie wavelength.
ParameterValue
p1×10⁻²⁴ kg·m/s
1λ = h/p = 6.626e-34 / 1e-24 = 6.626×10⁻¹⁰ m
Result 6.63×10⁻¹⁰ m ✓ Wavelength
Scenario: A proton has p = 5×10⁻²⁴ kg·m/s. Find λ.
ParameterValue
p5×10⁻²⁴
1λ = 6.626e-34 / 5e-24 = 1.325×10⁻¹⁰ m
Result 1.33×10⁻¹⁰ m ✓ Shorter
Key insight: λ = h/p – matter has wave properties, with wavelength inversely proportional to momentum.

Common mistakes

  • Momentum p: For a particle – p = mv (non‑relativistic) or relativistic.
  • de Broglie wavelength λ: In metres – typically very small for macroscopic objects.
  • Planck’s constant h: 6.626×10⁻³⁴ J·s.
  • Wave‑particle duality: Applicable to all matter, not just subatomic particles.
  • Units: p in kg·m/s → λ in m.

Applications

The de Broglie wavelength, λ = h/p, associates a wavelength with a particle, highlighting the wave‑particle duality. This concept is essential in quantum mechanics and is used in electron microscopy, neutron diffraction, and particle physics. Engineers apply it in the design of electron beam lithography, in scanning tunnelling microscopes, and in materials characterisation. The wavelength of electrons determines the resolution in electron microscopes. By understanding de Broglie's relation, professionals can exploit wave properties of matter to achieve high‑resolution imaging and to study the structure of matter at the atomic level.

  • Design of electron microscopes (TEM, SEM)
  • Electron beam lithography for semiconductor fabrication
  • Neutron diffraction for crystal structure analysis
  • Scanning tunnelling microscopy (STM)
  • Quantum interference and atom optics

Frequently Asked Questions

Q01What is the de Broglie wavelength of a particle?
A01

The de Broglie wavelength is the wavelength associated with a moving particle, given by λ = h/p, where h is Planck's constant and p is the momentum (p = mv for non‑relativistic particles). It reflects the wave‑particle duality of matter.

Q02What is the common mistake when applying this formula?
A02

Applying it to macroscopic objects (e.g., a baseball) where the wavelength is incredibly small and undetectable. The wave properties are only observable for microscopic particles (e.g., electrons).

Q03What is the de Broglie wavelength of an electron accelerated through 1 V?
A03

The electron gains kinetic energy 1 eV = 1.6×10⁻¹⁹ J. Its momentum is p = √(2mE). Using h, λ ≈ 1.23 nm. This is comparable to atomic spacings.

Q04What is the significance of the de Broglie wavelength in electron microscopy?
A04

Electron microscopes use the wave nature of electrons to achieve much higher resolution than optical microscopes, because the de Broglie wavelength of electrons is much smaller than visible light.

Q05How does the de Broglie wavelength change with speed?
A05

As speed increases, momentum increases, so wavelength decreases.

Q06What is the relativistic form of de Broglie wavelength?
A06

For particles moving close to the speed of light, use λ = h / (γ·m·v), where γ is the Lorentz factor.

Q07What is the Bohr model and how does de Broglie explain it?
A07

Bohr proposed that electrons orbit the nucleus only in circular orbits where the circumference equals an integer multiple of the de Broglie wavelength: 2πr = nλ. This quantises angular momentum.

Q08What are some experiments that confirmed de Broglie's hypothesis?
A08

The Davisson‑Germer experiment (electron diffraction) and the Thomson experiment confirmed the wave nature of electrons.