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Time Dilation (Special Relativity)

Calculates how much time appears to slow down for an object moving at a significant fraction of the speed of light, as observed from a stationary reference frame.

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Time Dilation CalculatorSpecial Relativity · Einstein

t' = t / √(1 − v²/c²)
t' = dilated time  ·  t = proper time  ·  v = relative velocity  ·  c = speed of light
⟹ Solvet', t, v
s
s
m/s
Please fix the errors above.
Solve for:
Presets:
Dilated Time (t')
t': t: v: v/c: γ:
✓ Copied!
Velocity / Speed of Light
Non‑relativistic (v/c < 0.1) Relativistic (0.1–0.9) Highly Relativistic (> 0.9)
t' = t / √(1 − v²/c²)  ·  c = 2.99792458 × 10⁸ m/s  ·  γ = 1/√(1 − v²/c²)

Interpretation

Time dilation: t' = t / √(1 – v²/c²), where t is proper time, t' is dilated time. Moving clocks run slower. Example: v=0.8c → γ=1/√(1-0.64)=1/0.6=1.667 → t'=1.667 t.

t' = t / sqrt(1 - v^2/c^2)
Time Dilation (Special Relativity)

Variables

SymbolQuantityUnit
t'Time interval measured in the stationary (observer's) frames
tProper time interval measured in the moving object's own frames
vSpeed of the moving objectm/s
cSpeed of light in vacuum3e8 m/s

What it means

Time dilation is a consequence of special relativity: a clock moving relative to an observer runs slower. The formula t' = γ t, where γ = 1/√(1 – v²/c²), relates the time interval t measured by an observer in the moving frame (proper time) to the time interval t' measured by an observer in a different frame. This effect has been verified experimentally with muon decays and atomic clocks on satellites. It is crucial for GPS synchronization, particle accelerators, and understanding high‑speed phenomena. The formula shows that as v approaches c, time slows down drastically. Understanding time dilation is essential for relativistic kinematics and modern physics.

Worked example

Time Dilation – Two Examples

Real‑World
Scenario: A clock on a spaceship moving at 1.5×10⁸ m/s records 1 second. How much time passes on Earth?
ParameterValue
t1 s
v1.5×10⁸ m/s
1γ = 1/√(1-v²/c²) = 1/√(1-0.5²) = 1/√0.75 = 1.155
2t' = γ·t = 1.155 × 1 = 1.155 s
Result 1.155 s ✓ Slower
Scenario: v = 2.7×10⁸ m/s (0.9c). Find time dilation factor for 1 second.
ParameterValue
v2.7×10⁸ m/s
1γ = 1/√(1-0.9²) = 1/√0.19 = 2.294
Result 2.294 s ✓ Time slows
Key insight: Time dilation: moving clocks run slower – t' = t/√(1-v²/c²).

Common mistakes

  • Speed v: Must be less than c – if v=c, the denominator becomes zero (infinite time).
  • Time t: Proper time (in the moving frame) – t is the time in the moving frame, tʹ is the time in the stationary frame? Actually, tʹ = t / γ, where γ = 1/√(1−v²/c²). Be careful about which frame is which.
  • Units: Both times in same units (seconds).
  • Time dilation: Moving clocks run slower – the moving observer measures a longer time.
  • Velocity addition: Not the same as Galilean addition – use relativistic velocity addition.

Applications

Time dilation, t' = t / √(1 − v²/c²), is a consequence of special relativity, stating that moving clocks run slow. This effect is real and must be accounted for in GPS satellite timing, particle accelerators, and high‑speed travel. Engineers use it to synchronise global navigation systems, to correct particle lifetimes in accelerators, and to design spacecraft navigation. The formula is also used in high‑energy physics to predict particle decay times. By understanding time dilation, professionals can ensure accurate timing for modern technology and deepen our understanding of the nature of space and time.

  • GPS satellite clock synchronisation and correction
  • Particle accelerator physics (muon lifetimes)
  • Spacecraft mission timing and relativistic corrections
  • High‑speed communication and network synchronisation
  • Educational demonstration of relativistic effects

Frequently Asked Questions

Q01What is time dilation in special relativity?
A01

Time dilation is the phenomenon where a moving clock runs slower compared to a stationary clock. The time interval measured by a moving observer (t') is shorter: t' = t / γ, where γ = 1/√(1 – v²/c²). More commonly, the proper time (t₀) is the time in the rest frame; the time in a moving frame is t = γ·t₀.

Q02What is the common mistake when applying time dilation?
A02

Applying ordinary (non‑relativistic) reasoning at speeds where the effect is significant. Also, confusing proper time and dilated time.

Q03What is the Lorentz factor γ?
A03

γ = 1 / √(1 – β²), where β = v/c. At low speeds, γ ≈ 1; at high speeds, γ > 1.

Q04What is the time dilation for a speed of 0.5c?
A04

γ = 1/√(1 – 0.25) = 1/√0.75 ≈ 1.155. So time passes about 15.5% slower for the moving object.

Q05What is the twin paradox?
A05

The twin paradox is a thought experiment where one twin travels at high speed and returns younger than the other. It is resolved by noting that the travelling twin changes inertial frames, so the situation is not symmetric.

Q06Is time dilation experimentally confirmed?
A06

Yes, it has been confirmed by many experiments, including muon decay, atomic clocks on airplanes, and particle accelerators.

Q07How does time dilation affect GPS satellites?
A07

GPS satellites have high speeds and are in weaker gravity; both effects (special and general relativity) cause their clocks to run at different rates and must be corrected for accurate positioning.

Q08What is the proper time?
A08

The proper time is the time measured by a clock that is at rest relative to the event. It is the shortest possible time interval between two events in spacetime.