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Turbojet Thrust Equation

This is the general thrust equation for an airbreathing jet engine. Thrust equals the mass flow rate times the difference between exhaust velocity and flight velocity, plus the pressure difference between the nozzle exit and the surrounding air times the exit area. At low speeds the momentum term dominates; at high speeds the pressure term becomes important. For example, a turbojet at takeoff produces thrust mainly from momentum, while at high altitude the pressure term contributes more. It is the fundamental equation of jet propulsion.

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Turbojet Thrust Equation Calculator

Solve the classic turbojet thrust equation F = ṁ·(Ve − V0) + Ae·(pe − p0) for any of its five unknowns — thrust, mass flow, exhaust velocity, freestream velocity, or nozzle exit area — with step-by-step math, a clean engine cross-section schematic, and companion propulsion metrics.

F = ṁ · ( Ve − V0 ) + Ae · ( pe − p0 )
Solve for
Net Thrust (F) Total net propulsive force. Combines the momentum thrust ṁ(Ve − V0) with the pressure thrust Ae(pe − p0). Typical: 20–50 kN for early turbojets, 60–140 kN for modern afterburning fighters.
N
Thrust must be greater than zero.
= 5,817 lbf = 2.638 tonne-force
Mass Flow Rate (ṁ) Mass flow of air passing through the engine core per unit time. Typical: 20–30 kg/s for a small turbojet, 50–80 kg/s for a mid-size one, 100–150 kg/s for a large afterburning turbojet.
kg/s
Mass flow must be greater than zero.
= 180,000 kg/h = 396,832 lb/h
Exhaust Velocity (Ve) Jet velocity at the nozzle exit plane, relative to the engine. Typical: 500–650 m/s for a non-afterburning turbojet, 700–900 m/s with afterburner, up to 1,000+ m/s for a high-performance afterburning turbojet.
m/s
Exhaust velocity must be greater than zero.
= 2,160 km/h = 1,166 kn · equivalent to M 1.76 at sea level
Freestream Velocity (V0) Flight velocity (true airspeed) of the aircraft through the air. For a static test, V0 = 0 and the full jet velocity contributes to thrust. For cruise at M 0.85 at 11 km, V0 ≈ 250 m/s.
m/s
Freestream velocity must be zero or greater.
= 900.0 km/h = 485.9 kn · equivalent to M 0.735 at sea level
Nozzle Exit Area (Ae) Cross-sectional area of the exhaust nozzle exit plane. Typical: 0.1–0.4 m² for a mid-size turbojet, 0.3–0.6 m² for a modern fighter engine, up to 1.0+ m² for a large afterburning engine with variable nozzle.
m²
Nozzle area must be greater than zero.
= 2,691 in² · equivalent diameter = 0.564 m
Exit Static Pressure (pe) Static pressure of the exhaust gas at the nozzle exit plane. For a perfectly expanded nozzle pe = p0 and the pressure thrust term vanishes. Above design point pe > p0 and pressure thrust is positive; below design point pe < p0 and it is negative.
Pa
Exit pressure must be greater than zero.
= 60.00 kPa = 8.702 psi
Ambient Pressure (p0) Static pressure of the surrounding atmosphere. Sea level ISA: 101,325 Pa. At 11 km: 22,632 Pa. At 15 km: 12,112 Pa. This is the reference against which the nozzle exit pressure is compared.
Pa
Ambient pressure must be greater than zero.
= 26.50 kPa = 3.844 psi · density altitude ≈ 9,000 m
NET THRUST (F)
25,875 N
5,817 lbf · momentum 17,500 N + pressure 8,375 N
MEDIUM TURBOJET / EARLY FIGHTER CLASS
F = ṁ·(V_e − V_0) + A_e·(p_e − p_0)
Step-by-step solution
Thrust vs. exhaust velocity
Current config ṁ × 0.7 ṁ × 1.3
Thrust vs. mass flow
Current Ve Ve × 0.7 Ve × 1.3
Sensitivity
Companion propulsion metrics
Turbojet thrust generation — live cross-section schematic
TURBOJET CROSS-SECTION · MOMENTUM + PRESSURE THRUST INTAKE COMPRESSOR COMBUSTOR TURBINE NOZZLE ṁ V₀ V_e hot exhaust A_e · p_e F (net) 25,875 N momentum thrust = ṁ · (V_e − V_0) = 17,500 N pressure thrust = A_e · (p_e − p_0) = 8,375 N F = 25,875 N
Air intake at mass flow ṁ and freestream velocity V0 Jet exhaust at velocity Ve (momentum thrust) Pressure thrust at the nozzle exit Ae·(pe − p0) Net thrust F combining both contributions
What the turbojet thrust equation really measures
Fnet thrust
=
ṁ·(Ve − V0)momentum thrust
+
Ae·(pe − p0)pressure thrust

Momentum thrust is the main contribution

The first term ṁ(Ve − V0) is pure Newton's second law: the change in momentum of the air passing through the engine. In most operating conditions it produces 80–95% of the total thrust. Its size is set by the product of mass flow and the velocity increment imparted by the engine.

Pressure thrust is the nozzle term

The second term Ae(pe − p0) accounts for the pressure force at the nozzle exit plane. When the nozzle is not perfectly expanded — that is, when exit pressure differs from ambient — this term contributes to net thrust. For a perfectly expanded nozzle it vanishes, and the thrust equation reduces to the pure momentum form.

Static vs. flight thrust

At zero flight velocity, the momentum thrust reduces to ṁ·Ve and thrust is maximum. As the aircraft accelerates, V0 rises and the momentum thrust falls — this is the well-known "ram drag" effect. The pressure thrust, however, is independent of flight speed and can partially offset the momentum loss at high Mach numbers.

Thrust is not the same as power

Thrust is a force; power is force times velocity. The useful propulsive power of a jet is F·V0, which grows with flight speed even as thrust falls. The propulsive efficiency is 2V0/(Ve + V0), which is why high-bypass turbofans with low jet velocities are more efficient than turbojets with high jet velocities at the same thrust level.

How to Use This Calculator

The turbojet thrust equation links five unknowns — thrust, mass flow, exhaust velocity, freestream velocity and nozzle exit area — with two additional inputs: exit pressure pe and ambient pressure p0. Pick which unknown you want to solve, then fill in the rest.

1. Choose what to solve for

Pick F, ṁ, Ve, V0, or Ae from the toggle. The calculator rearranges the thrust equation for your chosen unknown, making the active field read-only while the others stay editable.

2. Use realistic presets

Presets cover typical values: thrust from 5 to 200 kN, mass flow from 10 to 150 kg/s, exhaust velocity from 400 to 950 m/s, freestream velocity from static to 450 m/s, nozzle area from 0.05 to 1.0 m², and pressures covering sea level to high-altitude conditions.

3. Set the pressure ratio correctly

The nozzle pressure thrust Ae(pe − p0) is positive when the nozzle is under-expanded (pe > p0) and negative when over-expanded. At a nozzle perfectly matched to ambient, pe = p0 and the pressure thrust term vanishes.

4. Read the result and verdict

The result card shows the solved value plus the split between momentum and pressure thrust. A colour-coded verdict classifies the thrust level from small turbojet through early fighter, modern fighter, and up to very large engine classes.

5. Check the schematic and charts

The cross-section schematic shows air flowing in at ṁ and V0, the compressor-combustor-turbine-nozzle sequence, the jet exiting at Ve, and the net thrust arrow. The chart plots F against Ve for three mass flows.

6. Switch to Advanced for depth

Advanced mode adds a chart of F vs. ṁ, a sensitivity check on +1% input changes, and companion metrics including momentum and pressure thrust split, jet power, propulsive efficiency, specific thrust, and fuel-flow proxy.

What This Tool Offers

Built around the classic turbojet thrust equation F = ṁ·(Ve − V0) + Ae·(pe − p0), the fundamental result of jet propulsion theory.

Five-way solving

Solve for net thrust, mass flow, exhaust velocity, freestream velocity, or nozzle exit area. The calculator rearranges the equation for whichever variable you choose.

Clean engine cross-section

A schematic showing intake, compressor, combustor, turbine, and nozzle, with arrows for the incoming air, the hot exhaust jet, and the net thrust force.

Thrust-class verdict

Each thrust level is classified from small turbojet through early fighter, modern fighter, high-thrust, and up to very large engine classes, with a coloured badge.

Altitude pressure presets

Ambient pressure presets covering sea level, 3 km, 6 km, 9 km, 13 km and 20 km — plus exit pressure presets from under-expanded to over-expanded nozzles.

Dual comparison charts

F vs. Ve for three mass flow values, plus an advanced F vs. ṁ chart for three exhaust velocities.

Reference tables

Typical turbojet parameters by aircraft class, momentum-vs-pressure split, and a full variable reference table with unit conversions.

Reference Tables & Conversions

A thrust unit converter, a thrust lookup grid, and typical turbojet parameters by aircraft class.

Thrust unit converter

N
kN
lbf
kgf
= 25,875 N = 25.875 kN = 5,817.3 lbf = 2,638.5 kgf

Thrust Lookup at Various Ve and ṁ

Computed from F = ṁ(Ve − V0) + Ae(pe − p0) with V0 = 250 m/s, Ae = 0.25 m², pe = 60,000 Pa, p0 = 26,500 Pa (pressure thrust = 8,375 N). Values in kN.

ṁ (kg/s)V_e = 400 m/sV_e = 500 m/sV_e = 600 m/sV_e = 700 m/sV_e = 850 m/s

Typical Turbojet Parameters by Aircraft Class

Representative values at takeoff, sea level static, non-afterburning unless noted.

ClassF (kN)ṁ (kg/s)V_e (m/s)A_e (m²)Notes
Cruise missile (small turbojet)3 – 68 – 12500 – 6000.05 – 0.10One-shot application, expendable
Early jet trainer (J85)12 – 1520 – 24550 – 6000.10 – 0.15Simple, robust, low bypass
Early fighter (J79, no AB)48 – 5575 – 85550 – 6200.25 – 0.32Supersonic capable with AB
Early fighter (J79, with AB)75 – 8075 – 85900 – 1,0000.35 – 0.45Afterburner nearly doubles thrust
Modern fighter (F404, dry)48 – 5560 – 70600 – 7000.25 – 0.35Low-bypass turbofan, more efficient
Modern fighter (F404, with AB)75 – 8560 – 70950 – 1,1000.40 – 0.55Full afterburner
Large afterburning (F110, with AB)125 – 140120 – 1401,000 – 1,1500.60 – 0.80F-15 / F-16 class

Variable Reference

SymbolMeaningTypical rangeUnits
FNet thrust3×10³ – 2×10⁵N
ṁMass flow rate through engine5 – 200kg/s
VeExhaust velocity at nozzle exit400 – 1,200m/s
V0Freestream (flight) velocity0 – 600m/s
AeNozzle exit area0.05 – 1.5m²
peExit static pressure10⁴ – 2×10⁵Pa
p0Ambient static pressure5×10³ – 101,325Pa

What Does the Turbojet Thrust Equation Measure?

The turbojet thrust equation is Newton's second law applied to a control volume around the engine. It says the net thrust is the sum of two contributions: the change in momentum of the air that passes through the engine, and the pressure force acting on the exhaust nozzle exit plane. Together they describe how much forward force the engine produces at any operating condition, and they form the basis of all jet-engine performance analysis.

Turbojet Thrust Formula

The defining relationship is:

F = ṁ · ( Ve − V0 ) + Ae · ( pe − p0 )

Rearranged to solve for the other four unknowns:

ṁ = [ F − Ae · ( pe − p0 ) ] / ( Ve − V0 )
Ve = V0 + [ F − Ae · ( pe − p0 ) ] / ṁ
V0 = Ve − [ F − Ae · ( pe − p0 ) ] / ṁ
Ae = [ F − ṁ · ( Ve − V0 ) ] / ( pe − p0 )

When the nozzle is perfectly expanded (pe = p0), the pressure term vanishes and the equation reduces to the pure momentum form F = ṁ(Ve − V0).

Turbojet Thrust Variables

SymbolMeaningNotes
FNet thrustTotal forward force produced by the engine
ṁMass flow rateMass of air passing through per unit time
VeExhaust velocityJet speed at the nozzle exit, relative to the engine
V0Freestream velocityFlight speed; zero for a static test
AeNozzle exit areaCross-sectional area at the exit plane
peExit static pressurePressure of the gas at the nozzle exit
p0Ambient static pressurePressure of the surrounding atmosphere

How Each Variable Affects Thrust

Momentum thrust is proportional to both mass flow and the velocity increment (Ve − V0). To double thrust you can double the mass flow, double the velocity increment, or split the increase between them. In practice the mass flow is fixed by the inlet size, so most of the thrust control comes from the engine's ability to accelerate the air — which is set by the combustion temperature and the nozzle expansion ratio.

The pressure thrust term is independent of flight speed and depends only on the nozzle exit area and the pressure difference across the exit plane. A convergent nozzle on a non-afterburning turbojet is usually operated in the perfectly expanded or slightly under-expanded regime, contributing a modest positive thrust. A variable-geometry convergent-divergent nozzle with afterburner has a much larger area and a much larger pressure difference, contributing a substantial fraction of total thrust. The engineer's job is to choose the nozzle geometry so that the pressure thrust term is positive over the entire flight envelope — otherwise the engine loses thrust whenever the nozzle is over-expanded.

Thrust Calculation Examples

Given: ṁ = 50 kg/s, Ve = 600 m/s, V0 = 250 m/s, Ae = 0.25 m², pe = 60,000 Pa, p0 = 26,500 Pa
Momentum thrust = 50 × (600 − 250) = 17,500 N
Pressure thrust = 0.25 × (60,000 − 26,500) = 8,375 N
F = 17,500 + 8,375 = 25,875 N
Given: F = 25,875 N, Ve = 600 m/s, V0 = 250 m/s, Ae = 0.25 m², pe = 60,000 Pa, p0 = 26,500 Pa — solve for ṁ
ṁ = [25,875 − 8,375] / (600 − 250) = 17,500 / 350 = 50 kg/s
Given: F = 25,875 N, ṁ = 50 kg/s, V0 = 250 m/s, Ae = 0.25 m², pe = 60,000 Pa, p0 = 26,500 Pa — solve for Ve
Ve = 250 + [25,875 − 8,375] / 50 = 250 + 350 = 600 m/s

Frequently Asked Questions

The two terms represent two distinct physical mechanisms. The momentum term ṁ(Ve − V0) is Newton's second law applied to the air passing through the engine — the change in its momentum per unit time becomes a reaction force on the engine. The pressure term Ae(pe − p0) is the net pressure force acting on the exit plane of the nozzle. If the nozzle were perfectly expanded (pe = p0), the pressure term would vanish and the equation would reduce to the simpler momentum-only form.

A nozzle is perfectly expanded when the static pressure of the exhaust gas at the nozzle exit plane exactly equals the ambient pressure p0. In this condition the pressure thrust term is zero and all the thrust comes from momentum. A nozzle can only be perfectly expanded at one specific operating point (called the design point); at other altitudes or throttle settings it is either under-expanded (pe > p0, positive pressure thrust) or over-expanded (pe < p0, negative pressure thrust). Variable-geometry nozzles are used on afterburning engines precisely so that the nozzle can be re-matched for different operating conditions.

Because the momentum thrust depends on the velocity increment (Ve − V0). As the aircraft accelerates, V0 rises while Ve stays roughly constant (it is set by the nozzle and combustion temperature), so the velocity increment falls. This effect is called ram drag, and it is one of the reasons jet thrust is usually quoted at sea level static conditions — those give the maximum value. The pressure thrust term, in contrast, does not depend on flight speed at all, so at very high Mach numbers the pressure term becomes a larger fraction of total thrust.

Specific thrust is the thrust per unit mass flow, F/ṁ, and it measures how effectively the engine accelerates each kilogram of air. For a turbojet, specific thrust is on the order of 500–900 N·s/kg at takeoff, while for a high-bypass turbofan it can be as low as 100–150 N·s/kg. Low specific thrust is good for fuel efficiency because it corresponds to a smaller velocity increment, which gives higher propulsive efficiency, but it requires a larger engine to produce a given thrust. There is always a trade between specific thrust (engine size) and fuel efficiency (specific fuel consumption).

Yes, with a small modification. A turbofan has two exhaust streams — the core (hot, high-speed) and the bypass (cold, lower-speed) — so the thrust equation is applied to each stream separately and the results are summed: F = ṁcore(Ve,core − V0) + ṁfan(Ve,fan − V0) + pressure thrust terms for each nozzle. The basic physics is identical; the only change is that momentum is computed stream-by-stream. The formula in this calculator is the single-stream turbojet case, which is the cleanest starting point for understanding the physics.

Gross thrust is the total force produced by the engine at the exhaust, Fg = ṁ·Ve + Ae(pe − p0). Ram drag is the momentum of the incoming air, Dram = ṁ·V0. Net thrust is the difference: Fn = Fg − Dram. The thrust equation in this calculator gives net thrust directly, which is the quantity that matters for aircraft performance. At high flight speeds the ram drag is substantial, and net thrust can be much smaller than gross thrust.

An afterburner burns additional fuel in the exhaust stream between the turbine and the nozzle, raising the exhaust temperature and hence the exhaust velocity Ve. Mass flow ṁ is essentially unchanged. The result is a large increase in momentum thrust — typically 50–70% more thrust at takeoff, and up to 100% at high Mach. The nozzle is opened wider to accommodate the higher volume flow, which also increases the exit area Ae and, if the exit is still under-expanded, increases the pressure thrust term as well. Both terms of the thrust equation rise with afterburner.

Calculating...

Variables

Symbol Quantity Unit
F Net thrust N
mdot Mass flow rate kg/s
V_e Exhaust velocity m/s
V_0 Freestream velocity m/s
A_e Exit area m2
p_e Exit static pressure Pa
p_0 Ambient pressure Pa

What it means

The turbojet thrust equation is similar to the rocket equation but accounts for the incoming air momentum. It shows that thrust is produced by the change in momentum of the airflow plus the pressure thrust at the nozzle exit. For a jet engine, the mass flow includes air and fuel. This equation is used to calculate thrust for given engine conditions and flight speed. It is fundamental for engine performance analysis and for sizing the engine for a given aircraft. Understanding this equation is essential for propulsion engineers.

Worked example

Turbojet Thrust – Two Examples

Real‑World
Scenario: ṁ = 50 kg/s, V_e = 600 m/s, V₀ = 230 m/s, fully expanded (p_e = p₀). Find thrust.
ParameterValue
ṁ50 kg/s
V_e600 m/s
V₀230 m/s
1F = ṁ·(V_e - V₀) = 50 × (600-230) = 50 × 370 = 18,500 N
Result 18.5 kN ✓ Moderate
Scenario: ṁ = 80, V_e = 650, V₀ = 250, A_e = 0.6, p_e = 101,500, p₀ = 101,325. Find thrust.
ParameterValue
ṁ80
V_e650
V₀250
A_e0.6
p_e-p₀175
1F = 80×(650-250) + 0.6×175 = 80×400 + 105 = 32,105 N
Result 32.1 kN ✓ Higher
Key insight: Turbojet thrust = momentum thrust + pressure thrust – net thrust.

Common mistakes

  • Turbojet thrust equation: F = ṁ·(V_e − V₀) + A_e·(p_e − p₀).
  • ṁ: Mass flow rate (kg/s).
  • V_e: Exit velocity (m/s).
  • V₀: Freestream velocity (m/s).
  • A_e: Exit area (m²).
  • p_e: Exit pressure (Pa).
  • p₀: Ambient pressure (Pa).
  • If nozzle is perfectly expanded, pressure term is zero.

Applications

The turbojet thrust equation, F = ṁ·(V_e − V_0) + A_e·(p_e − p_0), is the general thrust expression for a turbojet, accounting for momentum and pressure thrust. It is used to design and evaluate turbojet engines, to size nozzles, and to compute thrust at different flight conditions. Engineers use this to integrate the engine with the airframe, to assess installation effects, and to predict performance. By applying this equation, aerospace engineers can optimise engine design for specific mission profiles, achieving the required thrust with minimal fuel consumption.

  • Turbojet engine design and performance prediction
  • Nozzle sizing and expansion ratio optimisation
  • Engine‑airframe integration and installation losses
  • Thrust measurement and validation in test cells
  • Performance analysis of gas turbine engines

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  • Published July 10, 2026
  • Last updated July 11, 2026