Formula & Calculator

Inverting Op-Amp Gain

The closed-loop voltage gain of an inverting operational amplifier configuration.

InstrumentationOp-Amps

Inverting Op-Amp Calculator Vout = −(Rf/Rin) · Vin

Vout = −(Rf / Rin) · Vin
Vout = output voltage (V)  ·  Rf = feedback resistor (Ω)  ·  Rin = input resistor (Ω)  ·  Vin = input voltage (V)
⟹ Solve Vout, Vin, Rf, Rin
V
V
Ω
Ω
Please fix the errors above.
Solve for:
Presets:
Output Voltage
Vout: Vin: Rf: Rin:
✓ Copied!
Output Voltage Gauge
Positive Negative Zero
Vout = −(Rf / Rin) · Vin  ·  Inverting configuration, gain = −Rf/Rin

Interpretation

Inverting op‑amp gain: V_out = −(R_f/R_in)·V_in inverts the input signal and scales it by the feedback‑to‑input resistance ratio.
The input impedance is approximately R_in.
Example: R_f=10kΩ, R_in=1kΩ, V_in=0.5V → V_out = −10 × 0.5 = −5V.

V_out = −(R_f/R_in)·V_in
Inverting Op-Amp Gain

Variables

SymbolQuantityUnit
V_outOutput voltageV
R_fFeedback resistorΩ
R_inInput resistorΩ
V_inInput voltageV

What it means

The inverting operational amplifier configuration has the output voltage V_out = −(R_f / R_in) · V_in. The negative sign indicates phase inversion. The gain is set by the ratio of the feedback resistor R_f to the input resistor R_in. The input impedance is approximately R_in. This configuration is widely used for summing amplifiers, integrators, and active filters. Because the non‑inverting input is grounded, the inverting input is a virtual ground (V− ≈ 0). The gain can be made less than, equal to, or greater than one (in magnitude). Example: With R_f=10kΩ and R_in=1kΩ, the gain is −10. A 0.5V input gives V_out = −10 * 0.5 = −5V. This is used for signal inversion and amplification.

Worked example

Inverting Op‑Amp – Practical Example

Real‑World
Scenario: An inverting amplifier uses Rf = 100 kΩ and Rin = 10 kΩ. Find the gain for a 1 V input.
ParameterValue
Rf100 kΩ
Rin10 kΩ
Vin1 V
FormulaVout = −(Rf/Rin)·Vin
1Gain = −100/10 = −10
2Vout = −10 × 1 = −10 V
Final Design Vout = −10 V ✓ Inverted gain
Why: The inverting configuration provides gain with phase inversion, determined by the resistor ratio.

Common mistakes

Watch unit consistency and the assumptions behind the formula; misapplying it outside its valid conditions is the most frequent error.

Applications

Inverting op‑amp gain V_out = −(R_f/R_in)·V_in inverts and scales the input signal. This is a standard building block for analog signal processing. Engineers use it for signal inversion, scaling, and summing. By selecting resistor values, they set the desired gain. This circuit is fundamental in analog electronics.

  • Signal inversion and phase shifting
  • Precision scaling and attenuator circuits
  • Summing amplifiers and analog computation
  • Active filter implementation
  • Educational understanding of op‑amp applications

Frequently Asked Questions

Q01What is the gain of an inverting operational amplifier?
A01

The voltage gain of an inverting op‑amp is V_out = −(R_f / R_in)·V_in. The negative sign indicates a 180° phase inversion.

Q02What is the input impedance of an inverting amplifier?
A02

The input impedance is approximately R_in (since the inverting input is at virtual ground). This is lower than the non‑inverting configuration.

Q03How do you choose R_f and R_in for a desired gain?
A03

Choose R_in based on the desired input impedance, then set R_f = −Gain × R_in. For example, for a gain of −10 with R_in = 1 kΩ, R_f = 10 kΩ.

Q04What are common mistakes when using the inverting amplifier?
A04

Common errors: 1) forgetting the negative sign, 2) using the wrong feedback resistor, 3) not considering the input bias current, 4) applying the formula to a non‑inverting circuit.

Q05What is the effect of the op‑amp's open‑loop gain on the closed‑loop gain?
A05

The closed‑loop gain is approximately −R_f/R_in as long as the open‑loop gain is much larger than the closed‑loop gain. At high frequencies, the gain rolls off.

Q06What are practical applications of inverting amplifiers?
A06

Used in summing amplifiers, active filters, and signal inversion.

Q07How does the virtual ground concept apply to the inverting amplifier?
A07

The inverting input is at virtual ground because the op‑amp forces the differential voltage to zero (assuming feedback). This simplifies analysis.

Q08What is the bandwidth of an inverting amplifier?
A08

The bandwidth is determined by the gain‑bandwidth product (GBW) of the op‑amp: BW = GBW / |Gain|. Higher gain reduces bandwidth.